The properties of the given elements are as follows:
Potassium, K;
- State of matter: Solid
- Melting point: 63.5 °C
- Conductivity: Good
- Solubility (H2O): reacts rapidly with water
Iodine, I;
- State of matter: solid
- Melting point: 113.5 °C
- Conductivity: very poor
- Solubility (H2O): negligible
Gold, Au;
- State of matter: solid
- Melting point: 1064 °C
- Conductivity: excellent
- Solubility (H2O): none
Germanium, Ge;
- State of matter: solid
- Melting point: 938.2 °C
- Conductivity: fair
- Solubility (H2O): none
Barium, Ba;
- State of matter: solid
- Melting point: 727 °C
- Conductivity: good
- Solubility (H2O): reacts strongly
Argon, Ar;
- State of matter: gas
- Melting point: -189.4 °C
- Conductivity: none
- Solubility (H2O): negligible
Chlorine Cl;
- State of matter: gas
- Melting point: -101.5 °C
- Conductivity: poor
- Solubility (H2O): slight
Rubidium, Rb;
- State of matter: solid
- Melting point: 39.48 °C
- Conductivity: good
- Solubility (H2O): reacts violently
Silver, Ag;
- State of matter: solid
- Melting point: 961.8 °C
- Conductivity: excellent
- Solubility (H2O): none
Calcium, Ca;
- State of matter: solid
- Melting point: 842 °C
- Conductivity: good
- Solubility (H2O): reacts
Silicon, Si;
- State of matter: solid
- Melting point: 1,410 °C
- Conductivity: intermediate
- Solubility (H2O): none
Xenon, Xe;
- State of matter: gas
- Melting point: -111.8 °C
- Conductivity: very poor
- Solubility (H2O): none
<h3>What are elements?</h3>
Elements are pure substances which are composed of similar atoms.
Elements are defined as substances which cannot be split into simpler substances by an ordinary chemical process.
Elements have different physical and chemical properties and can be classified into:
- metals
- semi-metals
- non-metals
In conclusion, the physical and chemical properties of the elements vary from metals to non-metals.
Learn more about elements at: brainly.com/question/6258301
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Answer:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
Explanation:
Chemical equation:
CO + O₂ → CO₂
Balanced chemical equation:
2CO + O₂ → 2CO₂
The standard enthalpy for the formation of CO = -110.5 kj/mol
The standard enthalpy for the formation of O₂ = 0 kj/mol
The standard enthalpy for the formation of CO₂ = -393.5 kj/mol
Now we will put the values in equation:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol + 0]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol]
ΔH0reaction = -283 kj/mol
Answer:
<span>If a mixture looks smooth and the same throughout it is probably <u>Homogeneous</u>.
Explanation:
Mixture is the combination of different compounds which are unreactive to each other.
Mixture are classified as ...
Solutions; in which the mixed compounds are thoroughly mixed and cannot be distinguished from each other and are said to be homogeneous. In solutions the size of solute is very small (i.e. Less than 1 nm).
Colloids; in which the solute is homogeneous visually but heterogeneous microscopically. The size of particles in this case is between 1 nm to 1 </span>μm.
Suspensions; in which the mixture is heterogeneous, the particle size is greater than 1 μm and settles down (precipitation) under the influence of gravity.
Answer:
Mg(NO4)2 is 180.3 g/mol
Explanation:
First find the substance formula.
Magnesium Nitrate.
Magnesium is a +2 charge.
Nitrate is a -1 charge.
So to balance the chemical formula,
We need 1 magnesium atom for every nitrate atom.
2(1) + 1(-2) = 0
So the substance formula is Mg(NO4)2.
Now find the molar mass of Mg(NO4)2.
Mg = 24.3 amu
N = 14.0 amu
O = 16.0 amu
They are three nitrogen and twelve oxygen atoms.
So you do this: 24.3 + 14.0(2) + 16.0(8) = 180.3 g/mol
So the molar is mass is 180.3 g/mol.
The final answer is Mg(NO4)2 is 180.3 g/mol
Hope it helped!
