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3 years ago

Calcium has an atomic number of 20. How many electrons does calcium lose when forming an ionic bond with another ion?

1 answer:

5 0

2 electrons. it has electron configuration of 2.8.8.2 hence the last 2 will be lost for it to gain stable.
if you need more explanation on periodic table you can reach me at [email protected]

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Which type of bond is formed between atoms of solid gold

goldfiish [28.3K]

Answer:

covalent bonds

Explanation:

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3 years ago

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Will the composition of water molecules vary depending on their source?

Alecsey [184]

Answer:

It does not matter where the sample of water came from or how it was prepared. Its composition, like that of every other compound, is fixed.

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3 years ago

What temperature does vodka freeze in fahrenheit?

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The answer is -11.2 fahrenheit.

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4 years ago

If the molecular weight of a semiconductor is 27.9 grams/mole and the diamond lattice constant is 0.503 nm, what is the density

adelina 88 [10]

Explanation:

The given data is as follows.

Mass = 27.9 g/mol

As we know that according to Avogadro's number there are $6.023 \times 10^{26}$ atom present in 1 mole. Therefore, weight of 1 atom will be as follows.

1 atoms weight = $\frac{38}{6.023 \times 10^{26}}$

In a diamond cubic cell, the number of atoms are 8. So, n = 8 for diamond cubic cell.

Therefore, total weight of atoms in a unit cell will be as follows.

= $\frac{8 \times 27.9 g/mol}{6.023 \times 10^{26}}$

= $37.06 \times 10^{-26}$

Now, we will calculate the volume of a lattice with lattice constant 'a' (cubic diamond) as follows.

= $a^{3}$

= $(0.503 \times 10^{-9})^{3}$

= $0.127 \times 10^{-27} m^{3}$

Formula to calculate density of diamond cell is as follows.

Density = $\frac{mass}{volume}$

= $\frac{37.06 \times 10^{-26}}{0.127 \times 10^{-27} m^{3}}$

= 2918.1 $g/m^{3}$

or, = 0.0029 g/cc (as 1 $m^{3} = 10^{6} cm^{3}$ )

Thus, we can conclude that density of given semiconductor in grams/cc is 0.0029 g/cc.

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3 years ago

Sort the following analytical techniques as either classical methods or instrumental methods.

Aleonysh [2.5K]

Answer:

Instrumental methods

surface analysis

high performance liquid chromatography

atomic spectroscopy

potentiometry

Classical methods

precipitation titration

gravimetric analysis

Explanation:

Instrumental methods of analysis are those analytical methods in which the responsibility of detection has been removed from human beings and placed on automated instruments while classical methods are those analytical methods in which the responsibility of detection remains the responsibility of human beings.

Many instrumental methods such as HPLC rely on computer screens as readout devices.

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3 years ago