Answer:
3 1/4 + 2x ≥ 6
Step-by-step explanation:
Let X equal the remaining time she needs to practice.
You would have 2x
The combined total needs to be 6 hours or greater.
You need to add the amount she already practiced to 2x.
Now you have: three and one fourth + 2x
This needs to be greater than or equal to 6.
I hope this helps you :)
(a) there are 8C2 = 28 ways of picking 2 girls from 8
And there are 21C4 = 5985 ways of picking 4 boys
Required number of ways for 2g / 4b = 28 * 5985 = 167,580
(b) at least 2 girls means combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or
6 girls.
2g/4b = 167,580 ways
3g/3b = 8C3 * 21C3 = 56 * 1330 = 74,480
4g/2b = 8C4* 21C2 = 70 * 210 = 14,700
5g 1b = 8C5* 21 = 56*21 = 1176
6 girls = 8C6 = 28
adding these up we get the answer to (b) which is 257,964
Answer:
$190
Step-by-step explanation:
800-230=570
570÷3=190
Answer:
The range is the output value or the y value.
You would work backwards to find the domain.
f(x) = 4x - 1 f(x) = 4x - 1
3 = 4x - 1 7 = 4x - 1
add 1 to both sides add 1 to both sides
4 = 4x 8 = 4x
divide both sides by 4 divide both sides by 4
x = 1 x = 2
f(x) = 4x - 1 f(x) = 4x - 1
11 = 4x - 1 15 = 4x - 1
add 1 to both sides add 1 to both sides
12 = 4x 16 = 4x
divide both sides by 4 divide both sides by 4
x = 3 x = 4
Domain { 1, 2, 3, 4}
Step-by-step explanation:
Answer:
Step-by-step explanation:
r=(2,-3,0) + t (1,0,-1)
r=(2+t, -3+0t,0+(-t))
x(t)=2+t
x(t)=t+2
y(t)=0t-3
y(t)=-3
z(t)=0+(-t)=-t
z(t)=0-t
z(t)=-t
