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3 years ago

Write an equation in slope-intercept form for the line with y-intercept −8 and slope 1/3.

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

8 0

Answer:

y = x/3 - 6

Step-by-step explanation:

yeah-ya......... right?

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Use the substitution method

vitfil [10]

Answer:

z = 9

z = 2

z = 5

z = 8

z = 11

Step-by-step explanation:

5 0

3 years ago

Not sure how I would solve this

Simora [160]

<h3>Answer: -6/5</h3>

Explanation:

The blue diagonal line goes through the two points (0,2) and (5,-4). These are shown as the dark blue enlarged points. You can pick any other points you want that are on the diagonal line, though these are the easiest as they stand out the most.

Use the slope formula to find the slope through these points

m = (y2-y1)/(x2-x1)

m = (-4-2)/(5-0)

m = (-6)/(5)

m = -6/5

The negative slope means the line goes downhill as you move from left to right along the diagonal line.

7 0

3 years ago

Find the mode for the scores 3,760, 5,200, 8,750, 4,400, 5,250

Semenov [28]

There is no mode in these scores.

This is because mode is when two numbers show up the same like 4 and 4.

8 0

2 years ago

A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

mestny [16]

Answer:

The value is $W= 2640 \ ft \cdot lb$

Step-by-step explanation:

From the question we are told that

The weight of the bucket is $F = 5 lb$

The depth of the well is $x_1 = 60 \ ft$

The weight of the water is $W_w = 42 lb$

The rate at which the bucket with water is pulled is $v = 1.5 \ ft/s$

The rate of the leak is $r = 0.15 lb/s$

Generally the workdone is mathematically represented as

$W = \int\limits^{x_1}_{x_o} {G(x)} \, dx$ ]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

$G(x) = F + (W_w- Ix)$

Here I is the rate of water loss in lb/ft mathematically represented as

$I = \frac{r}{v}$

=> $I = \frac{0.15 }{1.5 }$

=> $I = 0.1$

$G(x) = 5 + (42- 0.1x)$

=> $G(x) = 47- 0.1x)$

$W = \int\limits^{60}_{0} {47- 0.1x} \, dx$ ]

=> $W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.$

=> $W= [47(60) - 0.05(60)^2]$

=> $W= 2640 \ ft \cdot lb$

7 0

3 years ago

Given the function f (x) = -2x -5, determine the value of f (-3). Please helpp

anyanavicka [17]

Answer: if you see my picture that the answer for your question

Step-by-step explanation: hope this help

3 0

3 years ago