The value of integration of y=16-
from x=-1 to x=1 is 94/3.
Given the equation y=16- and the limit of the integral be x=-1,x=1.
We are required to find the value of integration of y=16- from x=-1 to x=1.
Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.
Integration is basically opposite of differentiation.
y=16-
Find the integration of 16-.
=16x-
Now find the value of integration from x=-1 to x=1.
=16(1)-
-16(-1)-
=16(1)-1/3+16-1/3
=32-2/3
=(96-2)/3
=94/3
Hence the value of integration of y=16- from x=-1 to x=1 is 94/3.
Learn more about integration at brainly.com/question/27419605
#SPJ4
The answer is X=19/2 y=10
Answer:
3x
Step-by-step explanation:
3 . x is 3x
Hello I hope this helps. I'm pretty sure this is the answer.
Part A: C
Part B: A
Answer:
An ISOSCELES TRIANGLE
Step-by-step explanation:
Given a triangle ABC with vertices at A(-5, 4), B(4, 1), and C(1, -8), to know the type of triangle this is, we need to find the three sides of the triangles by taking the distance between the points.
Distance between two points is expressed as:
D = √(x2-x1)²+(y2-y1)²
For side |AB|:
A(-5, 4) and B(4, 1)
|AB| = √(4-(-5))²+(1-4)²
|AB| = √9²+3²
|AB| = √90
For side |BC|
B(4, 1), and C(1, -8)
|BC| =√(1-4)²+(-8-1)²
|BC| = √3²+9²
|BC| = √90
For side |AC|:
A(-5, 4) and C(1, -8).
|AC| = √(1-(-5))²+(-8-4)²
|AC| = √6²+12²
|AC| = √36+144
|AC| = √180
Based on the distances, it is seen that side AB and BC are equal which shows that two sides of the triangle are equal. A triangle that has two of its sides to be equal is known as an ISOSCELES TRIANGLE. Therefore the term that correctly describes the triangle is an isosceles triangle.
