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topjm [15]
2 years ago
6

Plot StartRoot 1.5 EndRoot and StartRoot 1.9 EndRoot on the number line to find which inequalities are true. Check all that appl

y. StartRoot 1.5 EndRoot < 1.5 StartRoot 1.9 EndRoot < 1.9 StartRoot 1.5 EndRoot < StartRoot 1.9 EndRoot 1.2 > StartRoot 1.5 EndRoot > 1.3 1.3 < StartRoot 1.9 EndRoot < 1.4

Physics
2 answers:
Vera_Pavlovna [14]2 years ago
4 0

Answer:

A, B, C, E

Explanation:

now gimme thanks please

Natali5045456 [20]2 years ago
4 0

Answer: 1 2 3 5 I got it right :D

Explanation:

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A 20 kg sled is pulled up a 10m tall hill. What work is done against gravity?
Digiron [165]

Answer:

1962

Explanation:

w = f × d

= 20×9.81 × 10

= 1962

5 0
3 years ago
car 1 drives 45 mph to the west and car 2 drives 30mph to the east . from the frame of reference of car 1, what is the velocity
Naya [18.7K]
Distance between the two cars is increasing at the rate of 85 mph. 

A passenger in Car-1 says that he is at rest in his own frame of reference,
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6 0
3 years ago
Read 2 more answers
A railroad car is pulled through the distance of 960 m by a train that did 578 kJ of work during this pull.
Wittaler [7]

Answer:

<h2>602.08 N</h2>

Explanation:

The force supplied by the train can be found by using the formula

f =   \frac{w}{d}  \\

w is the workdone

d is the distance

From the question we have

f =  \frac{578000}{960}  \\  = 602.083333...

We have the final answer as

<h3>602.08 N</h3>

Hope this helps you

7 0
3 years ago
If a resource is non renewable, it ____
Karolina [17]

it cannot be reuse and replaced for long period of time.hope it helps u

4 0
3 years ago
Parasaurolophus was a dinosaur whose distinguishing feature was a hollow crest on the head. The 1.5-m-long hollow tube in the cr
Oksi-84 [34.3K]

Answer:

f1 = 58.3Hz, f2 = 175Hz, f3 = 291.6Hz

Explanation:

lets assume speed of sound is 350 m/s.

frequencies of a standing wave modes of an open-close tube of length L

fm = m(v/4L)

where m is 1,3,5,7......

and fm = mf1

where f1 = fundamental frequency

so therefore: f1 = 350 x 4 / 1.5

f1 = 58.3Hz

f2 = 3 x 58.3

f2 = 175Hz

f3 = 5 x 58.3

f3 = 291.6Hz

5 0
3 years ago
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