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topjm [15]
2 years ago
6

Plot StartRoot 1.5 EndRoot and StartRoot 1.9 EndRoot on the number line to find which inequalities are true. Check all that appl

y. StartRoot 1.5 EndRoot < 1.5 StartRoot 1.9 EndRoot < 1.9 StartRoot 1.5 EndRoot < StartRoot 1.9 EndRoot 1.2 > StartRoot 1.5 EndRoot > 1.3 1.3 < StartRoot 1.9 EndRoot < 1.4

Physics
2 answers:
Vera_Pavlovna [14]2 years ago
4 0

Answer:

A, B, C, E

Explanation:

now gimme thanks please

Natali5045456 [20]2 years ago
4 0

Answer: 1 2 3 5 I got it right :D

Explanation:

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Please help me with the question below the best answer with an explanation will get brainliest
lesya [120]

Answer:

B

Explanation:

i hope this is correct.

6 0
2 years ago
Earth's inner core is:a dense ball of solid metal
hram777 [196]
What is one effect of steroid abuse in professional sports?
AThey cause athletes to stop training hard incorrect answer
BThey allow some competitors to gain an unfair advantage incorrect answer
CThey cause athletes to stop competing to win incorrect answer
DThey cause athletes to become selfish
7 0
3 years ago
How much force is required to cause an object with a mass of 850 kg to accelerate at a rate of 2 meters per second squared (m/s^
arlik [135]

Answer:

How much force is required to cause an object with a mass of 850 kg to accelerate at a rate of 2 meters per second squared (m/s^2)?

Explanation:

<em>1700N </em>

<em> Mass multiplied by acceleration gives you the amount of force needed for it.</em>

3 0
2 years ago
Read 2 more answers
A(n) 7.7-kg object is sliding across the ice at 2.34 m/s in the positive x direction. An internal explosion occurs, splitting th
-BARSIC- [3]

Answer:

Average acceleration on first part of the chunk is given as

a_1 = 13.125 m/s^2

Average acceleration on second part of the chunk is given as

a_2 = -13.125 m/s^2

Explanation:

By momentum conservation along x direction we will have

mv_i = \frac{m}{2}v_1 + \frac{m}{2}v_2

so we have

v_1 + v_2 = 2v

v_1 + v_2 = 4.68

also by energy conservation

\frac{1}{2}(\frac{m}{2})v_1^2 + \frac{1}{2}(\frac{m}{2})v_2^2 - \frac{1}{2}mv^2 = 17 J

\frac{1}{4}m(v_1^2 + v_2^2) - \frac{1}{2}mv^2 = 17

(v_1^2 + v_2^2) - 2v^2 = \frac{4}{7.7}(17)

(4.68 - v_2)^2 + v_2^2 - 2v^2 = 8.83

21.9 + 2v_2^2 - 9.36 v_2 - 10.95 = 8.83

2v_2^2 - 9.36v_2 + 2.12 = 0

by solving above equation we will have

v_1 = 4.44 m/s

v_2 = 0.24 m/s

Average acceleration on first part of the chunk is given as

a_1 = \frac{4.44 - 2.34}{0.16}

a_1 = 13.125 m/s^2

Average acceleration on second part of the chunk is given as

a_2 = \frac{0.24 - 2.34}{0.16}

a_2 = -13.125 m/s^2

5 0
3 years ago
Current is the movement of positive charges called electrons.
spayn [35]

Answer:

False -> negative charge

7 0
2 years ago
Read 2 more answers
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