The distance traveled by the box over the first 4 s is 16 m.
To solve the problem above, First, we apply newton's Fundamental equation of force.
<h3 /><h3>Newton's fundamental equation of force:</h3>
F = ma...................... Equation 1
Where
- F = Force
- m = mass of the box
- a = acceleration
make "a " the subject of the equation
a = F/m...................... Equation 2
From the question,
Given:
Substitute these values into equation 2
a = 10/5
a = 2 m/s²
Finally, we use the equation of motion to calculate the distance it will travel over the given period of time.
<h3><u>Equation of motion</u></h3>
s = ut+at²/2........................... Equation 3
Where:
- s = total distance traveled
- t = time
- u = initial velocity
Given:
- t = 4 s
- u = 0 m/s (at rest)
Substitute these values into equation 3
- s = 0(4)+(2×4²)/2
- s = 0+32/2
- s = 16 m
Hence, the distance traveled by the box over the first 4 s is 16 m
Learn more about Newton's fundamental equation here: brainly.com/question/13370981
