Question

A 5 kg box is lying at rest on a frictionless surface. If you push it with a constant net force of 10 N, how far will it travel over the first 4 s

Answer 1

The distance traveled by the box over the first 4 s  is 16 m.

To solve the problem above,  First, we apply newton's Fundamental equation of force.

Newton's fundamental equation of force:

F = ma...................... Equation 1

Where

• F = Force
• m = mass of the box
• a = acceleration

make "a " the subject of the equation

a = F/m...................... Equation 2

From the question,

Given:

• F = 10 N
• m = 5 kg

Substitute these values into equation 2

a = 10/5

a = 2 m/s²

Finally, we use the equation of motion to calculate the distance it will travel over the given period of time.

Equation of motion

s = ut+at²/2........................... Equation 3

Where:

• s = total distance traveled
• t = time
• u = initial velocity

Given:

• t = 4 s
• u = 0 m/s (at rest)

• a = 2 m/s²

Substitute these values into equation 3

• s = 0(4)+(2×4²)/2
• s = 0+32/2
• s = 16 m

Hence, the distance traveled by the box over the first 4 s  is 16 m

Learn more about Newton's fundamental equation here: brainly.com/question/13370981