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Katen [24]
3 years ago
12

The more _________ an electron has, the further away it can be from the nucleus. mass

Physics
2 answers:
Monica [59]3 years ago
4 0

Answer:

ectron's further from the nucleus are held more weakly by the nucleus, and thus can be removed by spending less energy. Hence we say they have higher energy. The Coulomb interaction energy between a nucleus of atomic number and an ele

sasho [114]3 years ago
3 0

Answer: the more energy  

Explanation:

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According to Ohm's law, a circuit with a high resistance _____. will have a low electric current will have a high electric curre
lyudmila [28]
Remark
When you are asked a question like this, the first thing to do is search out a formula and put some limits on it.

Formula
I = E/R which comes from E = IR. To get to the derived formula, divide both sides by R
E/R = I*R/R
E/R = I

Discussion
This is an inverse relationship. That means that as one goes up the other one will go down. 

So in this case you keep E constant and you manipulate R and look at your results for I

Case 1

Let us say that E = 10 volts
Let us also say the R = 10 ohms

I = E/R
I = 10/10
I = 1 ohm

Case Two
Let's raise the Resistance to 100 ohms
E = 10
R = 100
I = 10/100 = 0.1 

Conclusion
As the Resistance goes up, the current goes down. Answer: A
8 0
3 years ago
Read 2 more answers
I need help on ideas for a science project.. (highschool ideas)
Nana76 [90]

A research question that would complete the third question you need that are related to the first 2 questions which are:

  • “what type of masks help prevent fog on glasses when breathing?”
  • “does a mask’s material affect the level of fog on glasses as an effect of breathing?”

Would be: "Are there any available masks that could prevent fog on glasses that could be improved upon"?

This new research question would help you find out if there is an already existing mask that could be made better.

<h3>What is a Research Question?</h3>

This refers to "a question that a research project sets out to answer". and seeks to give answers to particular phenomena.

Hence, we can see that the new research question Would be: "Are there any available masks that could prevent fog on glasses that could be improved upon"?

This new research question would help you find out if there is an already existing mask that could be made better.

Read more about research questions here:

brainly.com/question/25257437

#SPJ1

8 0
1 year ago
A 10-N force is needed to move an object with a constant velocity of 5.0 m/s. What power must be delivered to the object by the
vagabundo [1.1K]

The power that must be delivered to the object by the force is 50 W

Power is defined as the rate of doing work. The power of an object in relation to the force and velocity is given by the following equation:

Power (P) = Force (F) × velocity (v)

P = F × v

From the question given above, the following data were obtained:

  • Force (F) = 10 N
  • Velocity (v) = 5 m/s
  • Power (P) =?

P = F × v

P = 10 × 5

<h3>P = 50 W </h3>

Thus, the power that must be delivered to the object by the force is 50 W

Learn more on power: brainly.com/question/19539420

5 0
2 years ago
Which principle states that the net electrical force on a specific charge is equal to the sum of the vector components of the ch
Softa [21]

Answer:

C. The superposition principle

Explanation:

:)

7 0
3 years ago
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Part A What will be the equilibrium temperature when a 227 g block of copper at 283 °C is placed in a 155 g aluminum calorimeter
stellarik [79]

Answer:

T = 20.84°C

Explanation:

From the law of conservation of energy:

Heat Lost by Copper Block = Heat Gained by Aluminum Calorimeter + Heat Gained by Water

m_cC_c\Delta T_c = m_wC_w\Delta T_w + m_aC_a\Delta T_a

where,

m_c = mass of copper = 227 g

m_w = mass of water = 844 g

m_a = mass of aluminum = 155 g

C_c = specific heat capacity of calorimeter = 385 J/kg.°C

C_w = specific heat capacity of water = 4200 J/kg.°C

C_a = specific heat capacity of aluminum = 890 J/kg.°C

\Delta T_c = change in temperature of copper = 283°C - T

\Delta T_w = change in temperature of water = T - 14.6°C

\Delta T_a = change in temperature of aluminum = T - 14.6°C

T = equilibrium temperature = ?

Therefore,

(227\ g)(385\ J/kg.^oC)(283^oC-T)=(844\ g)(4200\ J/kg.^oC)(T-14.6^oC)+(155\ g)(890\ J/kg.^oC)(T-14.6^oC)\\\\24732785\ J - (87395\ J/^oC) T = (3544800\ J/^oC) T - 51754080\ J+ (137950\ J/^oC) T-2014070\ J\\\\24732785\ J +51754080\ J+2014070\ J = (3544800\ J/^oC) T+(137950\ J/^oC+(87395\ J/^oC) T\\\\78560935\ J = (3770145\ J/^oC) T\\\\T = \frac{78560935\ J}{3770145\ J/^oC}

<u>T = 20.84°C</u>

8 0
2 years ago
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