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3 years ago

10

Geometry question, i have some more on my profile please help!!!!

1 answer:

Marysya12 [62]3 years ago

3 0

Answer:

Vertical angles are congruent

Step-by-step explanation:

vertical angles intersect, usually forming a X shape, and have to always be equal

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Which of the following questions could be used to represent the equation 4 - X= 28?

rosijanka [135]

Answer:

$-24$

Step-by-step explanation:

$4 - -24= 28\\x=-24$

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3 years ago

A 12 foot ladder is placed against the side of the building. The base of the ladder is placed at an angle of 68° with the ground

3241004551 [841]

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Step-by-step explanation:

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3 years ago

Work out (1/8)*2 <br> give your anwser as a fraction in its simplest form

ikadub [295]

Answer:

1/4

Step-by-step explanation:

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3 years ago

Someone plz help me with this asap!!!!!

Bas_tet [7]

Answer:

1.) $x=8\sqrt{3};y=16$

2.) $x=1;y=\frac{\sqrt{3}}{2}$

3.) $x=28 ; y=14\sqrt{3}$

4.) $x=24 ; y=12\sqrt{3}$

5.) $x=4\sqrt{3};y=8\sqrt{3}$

6.) $x=\frac{8\sqrt{3}}{3};y=\frac{16\sqrt{3}}{3}$

Step-by-step explanation:

Use the 30°-60°-90° formulas:

a. $longer$ $leg=\sqrt{3}*shorter$ $leg$

b. $hypotenuse=2*shorter$ $leg$

1.) Insert values for a:

$x=\sqrt{3}*8$

Simplify:

$x=8\sqrt{3}$

Insert values for b:

$y=2*8$

Simplify:

$y=16$

2.) Insert values for a:

$y=\sqrt{3}*\frac{1}{2}$

Simplify:

$y=\frac{\sqrt{3}}{2}$

Insert values for b:

$x=2*\frac{1}{2}$

Simplify:

$x=1$

3.) Insert values for a:

$y=\sqrt{3}*14$

Simplify:

$y=14\sqrt{3}$

Insert values for b:

$x=2*14$

Simplify:

$x=28$

4.)Insert values for a:

$y=\sqrt{3}*12$

Simplify:

$y=12\sqrt{3}$

Insert values for b:

$x=2*12$

Simplify:

$x=24$

5.) Insert values for a:

$12=\sqrt{3}*x$

Divide both sides by $\sqrt{3}$ and rationalize:

$\frac{12}{\sqrt{3}}=\frac{\sqrt{3}*x}{\sqrt{3}}\\\\\frac{12}{\sqrt{3}}=x\\\\\frac{\sqrt{3}}{\sqrt{3}}*\frac{12}{\sqrt{3}}\\\\\frac{12\sqrt{3}}{\sqrt{9}}\\\\\frac{12\sqrt{3}}{3}\\\\4\sqrt{3}=x$

Flip:

$x=4\sqrt{3}$

Insert values for b:

$y=2*4\sqrt{3}$

Simplify:

$y=8\sqrt{3}$

6.) Insert values for a:

$8=\sqrt{3}*x$

Divide both sides by $\sqrt{3}$ and rationalize:

$\frac{8}{\sqrt{3}}=\frac{\sqrt{3}*x}{\sqrt{3}}\\\\\frac{8}{\sqrt{3}}=x\\\\\frac{\sqrt{3}}{\sqrt{3}}*\frac{8}{\sqrt{3}}\\\\\frac{8\sqrt{3}}{\sqrt{9}}\\\\\frac{8\sqrt{3}}{3}=x$

Flip:

$x=\frac{8\sqrt{3}}{3}$

Insert values for b:

$y=2*\frac{8\sqrt{3}}{3}$

Simplify:

$y=\frac{16\sqrt{3}}{3}$

Finito.

5 0

3 years ago

Solve using substitution y = 4 - 2x + 4y = 12

tensa zangetsu [6.8K]

ANSWER:

The value of x is 2 and of y is 4

$(2,4)$

STEP-BY-STEP EXPLANATION:

We have the following equation system

$\begin{gathered} y=4 \\ -2x+4y=12 \end{gathered}$

solving for substitution:

$\begin{gathered} -2x+4\cdot4=12 \\ -2x+16=12 \\ -2x=12-16 \\ x=\frac{-4}{-2} \\ x=2 \end{gathered}$

5 0

1 year ago