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2 years ago

Construct a quadrilateral TRUE, TR = 4 cm, RU = 5 cm, UE = 4.5 cm, angleR = 60° and angleU =90°

Mathematics

1 answer:

Pavel [41]2 years ago

6 0

Step-by-step explanation:

Hey

Sup

Here is the rough figure of how to construct Quadrilateral TRUE....

Follow this rough diagram and construct the quadrilateral according to it....

HOPE THIS ROUGH DIAGRAM HELPS YOU :)

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Answer:

$\boxed{\sf \ \ \ \dfrac{18}{(x-7)(x+12)(x+30)} \ \ \ }$

Step-by-step explanation:

hello,

first of all we will study the quadratic expressions

we can write that, (the different answers provide good clues :-) )

$x^2+5x-84=(x-7)(x+12)$

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so first of all as we cannot divide by 0 we need to take x different from 7, -12 and -30 and then we can write

$\dfrac{1}{x^2+5x-48}-\dfrac{1}{x^2+23x-210}=\dfrac{1}{(x-7)(x+12)}-\dfrac{1}{(x-7)(x+30)}\\\\=\dfrac{(x+30) -(x+12)}{(x-7)(x+12)(x+30)}=\dfrac{x+30-x-12}{(x-7)(x+12)(x+30)}\\\\=\dfrac{18}{(x-7)(x+12)(x+30)}$

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Construct a quadrilateral TRUE, TR = 4 cm, RU = 5 cm, UE = 4.5 cm, angleR = 60° and angleU =90°​

Construct a quadrilateral TRUE, TR = 4 cm, RU = 5 cm, UE = 4.5 cm, angleR = 60° and angleU =90°