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Degger [83]
2 years ago
6

3) How many moles are in 22 grams of argon?

Chemistry
1 answer:
professor190 [17]2 years ago
7 0

Answer:

4) 0.5507 Mol Ar

5) 44.548 Mol AgNO3

6) 2.16107 Mol Li

Explanation:

Divide = grams to mol and mol to molecules

Multiply = molecules to mol and mol to grams.

3) 22 <em>g of Ar</em>           1 mol                   22

-------------------- * ---------------------- = ------------ (turn to decimal) = 0.5507 Mol Ar

                           39.948 <em>g of Ar</em>     39.948

4) AgNO3 = (Ag;  39.948) (N; 14.007) (O^3; 48)  

39.948 + 14.007 + 48 = 101.955

   7.4 x 10^23 Mc    6.02 x 10^23 Mc

  ---------------------- * ------------------------- = 44.548 Mol AgNO3

                                        1 mol        

5)

15g           1 Mol             15

------- * ------------------- = --------- (turn to decimal) = 2.16107 Mol Li

            6.941 g of Li     6.941

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7. How many moles are in 5 x 10 2 atoms of gold?
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Answer:

8.3028894e-22

Explanation:

5x10^2 atoms/1 x 1 mol/6.022x10^23

7 0
3 years ago
The penguin has a ___ body that helps it to move quickly in water.
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The penguin has a sleek body that helps it to move quickly in water.
7 0
3 years ago
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Predict whether each of the following is soluble in water or not.
wlad13 [49]

Answer:

The soluble in water are a and b. c is not soluble in water

Explanation:

The water solubility of a compound, it depends its polarity (. KHSO4 has several polar molecules, actually it has ions charged positively like K and H, and charged negatively like sulfate (SO4-2). When it happens, molecules can do hydrogen bridges with water. It is because of above, KHSO4 can be used in wine making. Something similar happens with propylen glycol but in this case the polar part is OH- ions. Benzene has not polar parts. It is totally apolar compound.

I hope my answer helps you

4 0
4 years ago
NEED HELP ASAP NOT DIFFICULT
Burka [1]
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.

Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
5 0
3 years ago
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Please solve for Cu,N,and O an dif you can show how cause ik confused
belka [17]

Cu⇒ 1 atom

N⇒2 atoms

O⇒6 atoms

Total 9 atoms

<h3>Further explanation  </h3>

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

<em>(empirical formula) n = molecular formula  </em>

Chemical formula : Cu(NO₃)₂

Number of Cu : 1

Number of N : 2

Number of O = 2 x 3 = 6

Total atoms in Cu(NO₃)₂ : 1 + 2 + 6 = 9

4 0
3 years ago
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