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Over [174]
3 years ago
8

A dryer sheet is attracted to your hand as your pull laundry from the dryer. Which of the following statements is true? Select a

ll that apply.
1. The dryer sheet is positively charged and your hand is negatively charged.
2. The dryer sheet is negatively charged and your hand is positively charged.
3. With the given information it is not possible to tell which charge either object has.
4. The dryer sheet and your hand have opposite charges.
5. The dryer sheet and your hand have the same charge.
Physics
2 answers:
bixtya [17]3 years ago
8 0

Answer:

2. The dryer sheet is negatively charged and your hand is positively charged.

4. The dryer sheet and your hand have opposite charges.

Explanation:

As we know that electrostatic force between two charges is given by

F = \frac{kq_1q_2}{r^2}

here we know that two charges here are of similar type i.e. either both are positive or both are negative then in that case the force between them is repulsive force and if the charges are of opposite sign then the electrostatic force between two charges are attraction type of force.

So here If our hand is attracted towards the dryer sheet then our hand and dryer sheet must have opposite charges due to which they are attracted.

Also we know that the electron affinity of dryer sheet is more due to which it has tendency not to lose the electron so here we can say dryer sheet is negatively charge and hand is positively charged

guapka [62]3 years ago
7 0
2. The dryer sheet is negatively charged and your hand is positively charged
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Answer:

u = 10.63 m/s

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Explanation:

For Take-off speed ..

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u² = \frac{Rg}{sin2\theta}

u^2 = \frac{9.1 x 9.80}{sin26}

u^2 = 113.17

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for Max height

using the standard h(max) equation ..

v^2 = (v_osin\theta)^2 -2gh

h =\frac{(v_o^2sin\theta)^2}{2g}

h  =  \frac{(113.17)(sin26)^2}{(2 x 9.80)}}

h = 1.10 m

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3 years ago
For every action, there is an equal and opposite reaction.
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Two sound waves have equal displacement amplitudes, but wave 1 has two-thirds the frequency of wave 2. What is the ratio of the
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Answer:

\dfrac{I_1}{I_2}=\dfrac{4}{9}

Explanation:

c = Speed of wave

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Intensity of sound is given by

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So,

I\propto \nu^2

We get

\dfrac{I_1}{I_2}=\dfrac{\nu_1^2}{\nu_2^2}\\\Rightarrow \dfrac{I_1}{I_2}=\dfrac{\dfrac{2}{3}^2\nu_2^2}{\nu_2^2}\\\Rightarrow \dfrac{I_1}{I_2}=\dfrac{4}{9}

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8 0
3 years ago
when a metal ball is heated through 30°c,it volume becomes 1.0018cm^3 if the linear expansivity of the material of the ball is 2
Vlad1618 [11]

Answer:

The original volume of the metal sphere is approximately 1 cm³

Explanation:

The given parameters are;

The temperature change of the metal ball, ΔT = 30°C = 30 K

The new volume of the metal ball, V₂  = 1.0018 cm³

The linear expansivity of the material ball, α = 2.0 × 10⁻⁵ K⁻¹

We have;

d₂ = d₁·(1 + α·ΔT)

Where;

d₁ = The original diameter of the metal ball

d₂ = The new diameter of the ball

From the volume of the ball, V₂, we have;

V₂ = 1.0018 cm³ = (4/3)×π×r₂³

Where;

r₂ = The new radius = d₂/2

∴ V₂ = 1.0018 cm³ = (4/3)×π×(d₂/2)³

∴ d₂ = ∛(2³ × 1.0018 cm³/((4/3) × π)) ≈ 1.241445 cm

d₁ = d₂/(1 + α·ΔT)

∴ d₁ ≈ 1.241445 cm/(1 + 2.0 × 10⁻⁵·K × 30 K) ≈ 1.24070058 cm

The original volume of the metal ball, V₁ = (4/3)×π×(d₁/2)³

∴ V₁ = (4/3)×π×(1.24070058/2)³ ≈ 0.99999902845 cm³ ≈ 1 cm³

The original volume of the metal sphere, V₁ ≈ 1 cm³.

8 0
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