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Over [174]
3 years ago
8

A dryer sheet is attracted to your hand as your pull laundry from the dryer. Which of the following statements is true? Select a

ll that apply.
1. The dryer sheet is positively charged and your hand is negatively charged.
2. The dryer sheet is negatively charged and your hand is positively charged.
3. With the given information it is not possible to tell which charge either object has.
4. The dryer sheet and your hand have opposite charges.
5. The dryer sheet and your hand have the same charge.
Physics
2 answers:
bixtya [17]3 years ago
8 0

Answer:

2. The dryer sheet is negatively charged and your hand is positively charged.

4. The dryer sheet and your hand have opposite charges.

Explanation:

As we know that electrostatic force between two charges is given by

F = \frac{kq_1q_2}{r^2}

here we know that two charges here are of similar type i.e. either both are positive or both are negative then in that case the force between them is repulsive force and if the charges are of opposite sign then the electrostatic force between two charges are attraction type of force.

So here If our hand is attracted towards the dryer sheet then our hand and dryer sheet must have opposite charges due to which they are attracted.

Also we know that the electron affinity of dryer sheet is more due to which it has tendency not to lose the electron so here we can say dryer sheet is negatively charge and hand is positively charged

guapka [62]3 years ago
7 0
2. The dryer sheet is negatively charged and your hand is positively charged
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Answer:

cần cung cấp 70 độ vì nước sôi ở 100°C

Explanation:

7 0
3 years ago
How to do this question
Anna71 [15]

Answer:

(a) 10 m/s

(b) 22.4 m/s

Explanation:

(a) Draw a free body diagram of the car when it is at the top of the loop.  There are two forces: weight force mg pulling down, and normal force N pushing down.

Sum of forces in the centripetal direction (towards the center):

∑F = ma

mg + N = mv²/r

At minimum speed, the normal force is 0.

mg = mv²/r

g = v²/r

v = √(gr)

v = √(10 m/s² × 10.0 m)

v = 10 m/s

(b) Energy is conserved.

Initial kinetic energy + initial potential energy = final kinetic energy

½ mv₀² + mgh = ½ mv²

v₀² + 2gh = v²

(10 m/s)² + 2 (10 m/s²) (20.0 m) = v²

v = 22.4 m/s

4 0
3 years ago
If Bert the Bat travels East at 200 meters in 10 seconds, what is his velocity?
dexar [7]

Answer:

20m/s due east

Explanation:

Given parameters:

Displacement eastward  = 200m

Time  = 10s

Unknown:

Velocity  = ?

Solution:

Velocity is the displacement divided by time;

    Velocity  = \frac{displacement}{time}  

 Velocity  = \frac{200}{10}    = 20m/s due east

4 0
3 years ago
In 2000, NASA placed a satellite in orbit around an asteroid. Consider a spherical asteroid with a mass of 1.40×1016 kg and a ra
Arturiano [62]

A) 8.11 m/s

For a satellite orbiting around an asteroid, the centripetal force is provided by the gravitational attraction between the satellite and the asteroid:

m\frac{v^2}{(R+h)}=\frac{GMm}{(R+h)^2}

where

m is the satellite's mass

v is the speed

R is the radius of the asteroide

h is the altitude of the satellite

G is the gravitational constant

M is the mass of the asteroid

Solving the equation for v, we find

v=\sqrt{\frac{GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

M=1.40\cdot 10^{16}kg

R=8.20 km=8200 m

h=6.00 km = 6000 m

Substituting into the formula,

v=\sqrt{\frac{(6.67\cdot 10^{-11})(1.40\cdot 10^{16}kg)}{8200 m+6000 m}}=8.11 m/s

B) 11.47 m/s

The escape speed of an object from the surface of a planet/asteroid is given by

v=\sqrt{\frac{2GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

M=1.40\cdot 10^{16}kg

R=8.20 km=8200 m

h=6.00 km = 6000 m

Substituting into the formula, we find:

v=\sqrt{\frac{2(6.67\cdot 10^{-11})(1.40\cdot 10^{16}kg)}{8200 m+6000 m}}=11.47 m/s

5 0
3 years ago
Which produces more energy:
Leya [2.2K]

Answer:

a) uranium

b) deuterium

Explanation:

For the first question, you can actually know this by simple logic. The nucleus of Ucranium, has more energy than a pair of deuterium. Ucranium has a mass number and atomic mass higher than deuterium, therefore, when you do a fission with ucranium in it's nucleous, this would be in energy higher than the deuterium.

However, in terms of mass only, the fissioning of 1 gram of Deuterium will produce more energy than 1 gram of uranium, basically because deuterium is lighter and has a lower molecular weight than ucranium. This means that because of this lower molecular weight, in 1 gram of deuterium will contain more number of atoms than in 1 g of uranium. The interaction with these atoms, will produce more energy than the energy produced by uranium.

3 0
3 years ago
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