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m_a_m_a [10]
3 years ago
13

An electric field can be modeled as lines of force radiating out into space.

Physics
1 answer:
Hatshy [7]3 years ago
5 0
Yes. Electric field lines are the imaginary lines that represents strength & direction of electric field due to a charge. It can be modeled as lines.

In short, Your Answer would be "True"

Hope this helps!
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A force of 900 N is applied to a 9kg object. How fast will it accelerate?
saul85 [17]

Answer:  15 m/s2

Explanation: I hope this helps or right because I learned this a few months ago

7 0
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Trava [24]
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What is the frequency of a microwave of wavelength 3cm?
navik [9.2K]

Frequency = (speed) / (wavelength)

Speed = 3 x 10⁸ m/s

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Frequency = (3 x 10⁸  m/s) / (0.03 m)

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5 0
3 years ago
Two parakeets sit on a swing with their combined center of mass 10.0 cm below the pivot. At what frequency do they swing?
Oksanka [162]

Answer:

1.58 Hz

Explanation:

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7 0
3 years ago
(a) find the magnitude of the gravitational force between a planet with mass 7.50 3 1024 kg and its moon, with mass 2.70 3 1022
anzhelika [568]
<span>The magnitude of the gravitational force between two bodies is the product of their masses divided by the square of the distance between them. So we have F = M1*M2 / r^2. M1 = 7.503 * 10e24 and M2 = 2.703 * 10e22 and r= 2.803 * 10e8; r^2 = 5.606 *10e16. So we have 7.503 *2.703 *10^(24+22) = 20.280 * 10^(46). Then we divide our answer by 5.606 * 10e16 which is the distance ; then we have 3.6175 * 10 e (46- 16) = 3.6175 * 10e30. To find the acceleration we use Newton's second law F = ma. F is 3.6175 * 10e30 and M is 7.503 * 10e24 so a = F/M and then we have 3.6175/7.503 * 10e (30-24) = 0.48 * 10e6. Similarly for moon, we have a = 3.6715/2.703 * 10e(30-22). = 1.358 * 10e8</span>
4 0
3 years ago
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