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fredd [130]
3 years ago
10

Suppose there is a uniform magnetic field, B, pointing into the page (so your index finger will point into the page). If the vel

ocityof a proton is straight up(thumb pointing up) then RHR2 shows that the force points to the left. What would the direction of the force be if the velocitywere a) down b) to the rightc) to the leftd) into the pagee) out of the page
Physics
1 answer:
Naily [24]3 years ago
3 0

Answer:

Explanation:

We shall show all given data in vector form and calculate the direction of force with the help of following formula

force F = q ( v x B )

q is charge , v is velocity and B is magnetic field.

Given B = - Bk ( i is  right  , j is  upwards  and k is straight up the page  )

v = v j

F = q ( vj x - Bk )

= -Bqvi

The direction is towards left .

a ) If velocity is down

v = - v j

F = q ( - vj x - bk )

= qvB i

Direction is right .

b ) v = v i

F = q ( vi x - Bk )

= qvB j

force is upwards

c ) v = - vi

F = q ( -vi x - Bk )

= -qvBj

force is downwards

d ) v = - v k

F = q( - vk x -Bk  )

= 0

No force will be created

e ) v =  v k

F = q(  vk x -Bk  )

= 0

No force will be created  

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Two samples of water are mixed together.
horrorfan [7]

Let the cold water go up x degrees.

Let the hot water go down 100 - x degrees.

The formula for heat exchange is m*c*delta t

Givens

Ice

deltat = x

m = 0.50 kg

c = 4.18

Hot water

deltat = 100 - x

m = 1.5 kg

c = 4.18

Formula

The heat up = heat down

0.50 * c * x = 1.5 * c * (100 - x)            Divide both sides by c

Solution

0.50 *x = 1.5*(100 - x)                          Remove the brackets.

0.5x = 150 - 1.5x                                  Add 1.5x to both sides.

0.5x + 1.5x = 150 - 1.5x + 1.5x             Combine like terms  

2x = 150                                               Divide by 2

x = 75

Answer

A

6 0
3 years ago
What type of decay has the release of electromagnetic energy from the nucleus and has the most penatrating power through other s
Verdich [7]

Answer:

Gamma decay

Explanation:

There are 3 types of radioactive decay:

- Alpha decay: in this decay, a nucleus emits an alpha particle (consisting of 2 protons and 2 neutrons, so a nucleus of helium). The alpha particle has a large charge (2e) and a large mass (4u), so it is strongly ionizing, and therefore loses energy faster while moving through matter, therefore its penetrating power is low (it can be easily stopped by a thin sheet of paper or by the skin)

- Beta decay: this decay occurs when a neutron in a nucleus turns into a proton, emitting a beta particle (a fast-moving electron) alongside with an antineutrino. The beta particle has a lower charge (e) and a smaller mass than the alpha particle, so it has a moderate penetrating power, being able to penetrate more than the alpha particle (the beta particle can be stopped by a thin sheet of aluminium)

- Gamma decay: this decay occurs when an excited nucleus decays emitting a gamma ray photon (which is electromagnetic energy with very high energy and frequency). The gamma ray photon has no charge and no mass, therefore it has the most penetrating power, being able to travel a much large distance before being absorbed by matter (several metres of concrete are required to stop gamma radiation.

So, the description in the question refers to gamma decay.

7 0
3 years ago
Describe how a multistage fitness test works and what it is intended to do
skad [1K]
Runners complete 20m continuous runs, going from one cone to another. they must get to one cone from another until a beep comes. each time, the time between the beeps decrease.
the multistage fitness test is mostly to measure the power of aerobic.
10 0
4 years ago
Which data from ocean rocks showed seafloor spreading and convinced scientists the theory of plate tectonics was valid?A.
Lena [83]
The Answer is B. paleomagnetism
3 0
4 years ago
A small earthquake starts a lamppost vibrating back and forth. The amplitude of the vibration of the top of the lamppost is 7.0
krok68 [10]

Answer:

(a) T=6.07s

(b) x_{max|4.0s}=3.62cm

Explanation:

For Part (a)

The initial amplitude is given as A=7.0 cm

Apply the equation x_{max}(t)=Ae^{-t/T} with  x_{max}(7.6s)=2.0cm we have:

x_{max}(t)=Ae^{-t/T}\\2.0cm=(7.0cm)e^{-7.6s/T}\\T=-\frac{7.6s}{ln(\frac{2.0cm}{7.0cm} )} \\T=6.07s

For Part (b)

Apply x_{max}(t)=Ae^{-t/T}  with t=4.0s and T=6.07s we have

x_{max}(t)=Ae^{-t/T}\\x_{max}(4.0s)=(7.0cm)e^{-4.0/6.07}\\x_{max|4.0s}=3.62cm

8 0
4 years ago
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