Question

Suppose you have a liquid solution containing two components, A and B. The boiling point of pure A is 46.0 C and the boiling point of pure B is 116.0 C. Your solution has a mole fraction of component A equal to 0.69, and the solution behaves as an ideal solution. What is the boiling point of this solution? (Choose the best answer - A,B,C, or D)

Answer 1

Answer:

67.7 °C

Explanation:

Since this solution has 2 substances, but not in the same proportion, you need to consider the fraction molar of each one and the boling point, it will be expected a higher temperature than the lower boiling point and a lower boiling point of the highest boiling point.

46 °C  x 0.69 = 31.74 °C

116°C x 0.31 = 35.96 °C

You add both: 31.74 °C + 35.96°C = 67.7 °C