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avanturin [10]
1 year ago
11

An object with a mass of 4.91 kg rests on a plane inclined 42.34 ° from horizontal. What is the component of the weight force th

at is perpendicular to the incline?
Physics
1 answer:
12345 [234]1 year ago
3 0

the perpendicular component will be = Wy

Wy = w * cos 42.34 = 48.11 N x cos 42.34 = 35.54 N

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Mithun wants to test if a convex lens produces an inverted image of an object placed at a distance away from the lens. Which of
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Answer:

(D) any of these objects can be used as long as all points on the object lie farther away from the lens than the focal length of the lens.

Points lying between the focal point and the lens will be erect and will not form an object visible on a screen.

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Which of the following is a purpose of rules in sports and games? (5 points)
ValentinkaMS [17]

Answer:

To keep everyone safe

Explanation:

Without rules people could get hurt

4 0
2 years ago
7. A ball of mass m makes a head-on elastic collision with a second ball (at rest) and rebounds with a speed equal to 0.450 its
emmasim [6.3K]

Answer:

mass of the second ball is 0.379m

Explanation:

Given;

mass of first ball = m

let initial velocity of first ball = u₁

let final velocity of first ball  = v₁ = 0.45u₁

let the mass of the second ball = m₂

initial velocity of the second ball, u₂ = 0

let the final velocity of the second ball = v₂

Apply the principle of conservation of linear momentum;

mu₁ + m₂u₂ = mv₁ + m₂v₂

mu₁  +  0  = 0.45u₁m + m₂v₂

mu₁  = 0.45u₁m + m₂v₂ -------- equation (i)

Velocity for elastic collision in one dimension;

u₁ + v₁ = u₂ + v₂

u₁ + 0.45u₁ = 0 + v₂

1.45u₁ = v₂ (final velocity of the second ball)

Substitute in v₂ into equation (i)

mu₁  = 0.45u₁m + m₂(1.45u₁)

mu₁ = 0.45u₁m + 1.45m₂u₁

mu₁ - 0.45u₁m = 1.45m₂u₁

0.55mu₁ = 1.45m₂u₁

divide both sides by u₁

0.55m = 1.45m₂

m₂ = 0.55m / 1.45

m₂ = 0.379m

Therefore, mass of the second ball is 0.379m (where m is mass of the first ball)

6 0
3 years ago
You have a 6.00 V power supply, and
ollegr [7]

Answer: 0.28 A

Explanation:

8 0
3 years ago
3. why is the sum of the maximum voltages across each element in a series r l c circuit usually greater than the maximum applied
Llana [10]

The sum of the maximum voltages across each element in a series RLC circuit is usually greater than the maximum applied voltage because voltages are added by vector addition.

<h3>What is the Kichoff's loop rule?</h3>

Kirchhoff's loop rule states that the algebraic sum of potential differences, as well as the voltage supplied by the voltage sources and resistances, in any loop must be equal to zero.

In a series RLCcircuit, the voltages are not added by scalar addition but by vector addition.

Kirchhoff's loop rule is not violated since the voltages across different elements in the circuit are not at their maximum values.

Therefore, the sum of the maximum voltages across each element in a series RLC circuit is usually greater than the maximum applied voltage because voltages are added by vector addition.

Learn more about Kichoff's loop rule at: https://brainly.in/question/35360816

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8 0
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