3 years ago

Help plz

Physics

2 answers:

olga2289 [7]3 years ago

6 0

Trail 3 and trial 5 oh dang son

Fittoniya [83]3 years ago

5 0

Yes u can actually voltages are 50 % more of coils than differs u can not be done in here but it was just me too and she was gone bye

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Express the vector R<br> B<br> in terms of A, B, C, and Ď, the edges of a<br> parallelogram.

Vadim26 [7]

Answer:

R=0.5B+0.5C+2A+D

Explanation:

By the triangular law of vector addition

vector R= vector B- vector D

As A,B,C,D are edges of the parallelogram,

A is parallel to D but opposite in direction.

Therefore

$A = (-D)$ ; $A//D$ ;

$2A=-2D$

B is parallel to C and in same direction.

$B//C\\B=C\\$

$0.5B=0.5C\\$

$R= B-D;\\R= 0.5B+0.5B-D;\\R=0.5B+0.5C-D;\\R=0.5B+0.5C-2D+D;\\R=0.5B+0.5C+2A+D;$

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The coefficent of static friction between the floor of a truck and a box resting on it is 0.38. The truck is traveling at 87.9 k

nekit [7.7K]

Answer:

$d=79.9m$

Explanation:

From the question we are told that:

coefficient of static friction $\mu=0.38$

Velocity $v=87.9=>24.41667m/s$

Generally the equation for Conservation of energy is mathematically given by

$\mu*mgd = 0.5 m v^2$

$d=\frac{0.5*24.42^2}{0.38*9.8}$

$d=79.9m$

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Nina is doing a workout where she runs at 50% speed for 3 minutes, 75% speed for 2 minutes, and 100% speed for 30 seconds. This

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a charge of 7.2x10^-5C is placed in an Electric field with a strength of 4.8x10^5N/C. if the Electric potential energy of the ch

Alecsey [184]

Answer:

$d= 2.2 m$

Explanation:

The data given in the question is

Charge : q = $7.2 \times 10^{-5} C$

Electric field Strength : E = $4.8 \times 10^{5} N/C$

Electrical potential Energy : U = $75J$

Let, the distance be "d"

So, the formula for Electrical potential energy is

$U= q \times E \times d$

Simplified formula for distance become

$d=\frac{U}{q \times E}$

Now , insert the value

$d=\frac{75 J}{7.2 \times 10^{-5}C \times 4.8 \times 10^5 N/C}$

or,

$d=2.17 m$

Rounding off

$d= 2.2 m$

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3 years ago