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CaHeK987 [17]
3 years ago
6

For the function , what is the maximum value?

Mathematics
1 answer:
andreev551 [17]3 years ago
3 0

Answer:

The maximum value of a function is the place where a function reaches its highest point, or vertex, on a graph.

I hope it helps.

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A group of 485 people take a canoe trip. They fill up all avalible canoes that each hold 3 people with 273 people. The rest of t
Jobisdone [24]
Answer:
3c=273
c=91
2c= 212
C= 106
c= 91+ 106= 197
so they will need 197 canoes total

Why:
So first you have to determine a set variable to represent the number of canoes, I chose C. Then you make an equation to represent the number of canoes 273 people will use if they group into 3's, from this I got 3c=273. Solve for C and get 91.
The remainder of the group which is 485-273= 212 will use canoes in groups of 2's. To represent this, 2c=212. Solve for C and get 106. Combine 106 and 91 to get the total number of canoes.
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Find the distance between the points given<br> (0, -6) and (9,6)
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Answer:

(9,12)

Step-by-step explanation:

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Brayden is going to invest in an account paying an interest rate of 4.3% compounded
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Find the 73rd term of the arithmetic sequence -28, -41, -54, ...
PolarNik [594]

Answer:

the 73rd term of the arithmetic sequence is -964.

Step-by-step explanation:

The common difference in this arithmetic sequence is 13.  This is obtained by subtracting 28 from 41.  The first term is a(1) = -28.

The arithmetic sequence formula is a(n) = a(1) + d(n - 1), where d is the common difference and -28 the first term.

Then, in this case, a(n) = -28 - 13(n - 1), and

a(73) = -28 - 13(73 - 1) = -964

3 0
2 years ago
Often sales of a new product grow rapidly at first and then level off with time. This is the case with the sales represented by
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Answer:

Here we have the function:

S(t) = 500 - 400*t^(-1)

Then the rate of change at the value t, will be:

S'(t) = dS(t)/dt

This differentiation will be:

S'(t) = -400/t^2

Then:

a) the rate of change at t = 1 is:

S'(1) =  -400/1^2 = -400

The rate of change after one year is -400

b) t = 10

S'(10) = -400/10^2 = -400/100 = -4

The rate of change after 10 years is -4, it reduced as the years passed, as expected.

7 0
3 years ago
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