The derivative is the gradient.
At any local Max's or min's the derivative graph will cut the x axis.
For example a graph x^2
The derivative will have a positive gradient as the gradient is increasing at the lower values then at x=0 the gradient is 0 so the derivative graph will pass the point (0,0). Remember that the derivative graph will be linear.
To get more detail find the points the graph crosses the x axis and put into for a(x-q)(x-p)=0 you will have to solve for 'a' by finding a point on the graph and substituting it in. Then you can find the derivative of that function and graph it
The surface area is 216
The Volume is 216
The diagonal is 10.392
Answer:
They have a y-value of 0. They are in Quadrant 1. They are not above or below the origin.
Step-by-step explanation:
Answer:
m = -2
Step-by-step explanation:
To get the slope of the line, we are going to use the 2-points slope equation form
That will be;
m = (y2-y1)/(x2-x1)
(x1,y1) = (-5,11)
(x2,y2) = (8,-15)
m = (-15-11)/(8-(-5)) = -26/13 = -2
The possible mistake she might have made is placing the x-values difference over the y and her formula will look like;
m = (x2-x1)/(y2-y1)
It is an error of switching the numerator for the denominator
Answer: 35
Just took a test on this