Question

write a formula for quadratic function if its graph has the vertex at point (0,6) and passes through the point (-1, -2)

Answer 1

Step-by-step explanation:

Use the vertex

$- 8 {x}^{2} + 6$

formula, we know that h is 0 and k is 6 so we get

$a(x {}^{2} ) + 6$

Now, we set that equal to y and plug in -1 for x and -2 for y to solve for a.

$a( (- 1) {}^{2} ) + 6 = - 2$

$a(1) + 6 = - 2$

$a = - 8$

So our formula is

$- 8( {x}^{2} ) + 6$

ir

$- 8 {x}^{2} + 6$