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3 years ago

Which are the coordinates of point K?

Mathematics

1 answer:

never [62]3 years ago

3 0

I need the graph first

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Suppose that P(n) is a propositional function. Determine for which improper subset of the domain of n the statement P(n) must be

Alinara [238K]

Answer:

a) P(n) is true for all 'n' in the set ; { 0,2,4,6,8 ….. }

b) P(n) is true for all 'n' in the set ; { 0,1,2,3,4,5 ............ }

Step-by-step explanation:

a) As P(0) is true

we will assume that

P(2) is true
P(4) is true
P(6) is true

this simply means that ; P(n) is true for all 'n' in the set

{ 0,2,4,6,8 ….. }

b) since P(0) and P(1) are true

we will assume that

P( 0+2 ) = P(2) is true

also P(1) and P(2) are true

we will assume that

P(1+2) = P(3) is true

Also from the previous answers it can be seen that P(2) + P(3) is true

we will assume

P(2+2) = P(4) is true

This simply means that P(n) is true for all 'n' in the set

{ 0,1,2,3,4,5 ............ }

8 0

2 years ago

12/2 as a whole number or mixed number

bogdanovich [222]

It is a mixed number because 12/2 can be written as 6 instead of 12/2

4 0

3 years ago

Read 2 more answers

Perimeter of triangle:20

goblinko [34]

Answer:

perimeter of rectangle= 2(4+X)

32=8+2x

32-8=2x

26=2x

26/2=X

14=X

perimeter of triangle=3×sides

20=3x

20/3=X

6.66=x

4 0

2 years ago

PLEASE HELPPPPPPPPPPPPPPPPP

Stels [109]

Answer:

Diameter = 43.96 $m^{2}$

Circumference = 153.86 $m^{2}$

8 0

3 years ago

Given: ∆AMK, MP ⊥ AK , MP = 10 m∠A = 72º, m∠PMK = 50° Find AM, MK, AK

mina [271]

Answer:

Step-by-step explanation:

The diagram of triangle AMK is shown on the attached photo. To determine AM, we would apply trigonometric ratio since triangle AMP is a right angle triangle.

Sin# = opposite/hypotenuse

Sin 72 = 10/AM

AMSin72 = 10

AM = 10/Sin72 = 10/0.9511

AM = 10.51

To determine MK,

Cos# = adjacent/hypotenuse

Cos 50 = 10/MK

MKCos50 = 10

MK = 10/Cos50 = 10/0.6428

MK = 15.6

AK = AP + KP

Tan# = opposite/adjacent

Tan 72 = 10/AP

AP tan 72 = 10

AP =10/tan72 = 10/ 3.0777 = 3.25

Tan 50 = KP/10

KP = 10tan50

KP= 10× 1.1918 = 11.918

Therefore,

AK = 3.25 + 11.918 = 15.168

3 0

3 years ago