Question

PLEASE HURRY!! 20 PTS!!

Answer 1

We have one of those equations already solved for y, so let's sub that one into the other one and solve the equation in terms of x only: $2x+( x^{2} -4x+3)=6$.  We will simplify that and at the same time bring the 6 over by subtraction to get a polynomial set to equal 0 that we can factor.  $x^{2} -2x-3=0$.  We will factor that to get (x-3)(x+1) for x values of x = 3 and x = -1.  a above is the choice that has the x values we need, -1 and 3.

Answer 2

B is the final answer!!! :)