Answer:
The objects kinetic energy increases as it falls from some height.
Scientists need creativity because, Scientists use creativity to decide which smaller questions are probably to yield results, consider feasible solutions to their questions, and devise approaches to check the ones solutions.
An good example would be using a Bunsen burner to heat water in a tin container. The flame initially heats the tin can by radiating heat. Conduction then transfers heat from the tin can to the water. The convection process causes the hot water to then climb to the top.
<h3>What is Bunsen Burner?</h3>
A laboratory piece of equipment known as a Bunsen burner, which bears Robert Bunsen's name, produces a single open gas flame and is used for heating, sterilization, and combustion. Natural gas, liquefied petroleum gas, such as propane, butane, or a combination, are all acceptable choices for the gas.
<h3>What three types of flames can you get from a Bunsen burner?</h3><h3>Bunsen burner flames come in three primary categories:</h3>
- Because it is simple to notice in a well-lit space, a yellow flame is also referred to as a safety flame.
- Flaming Blue. A burner's specific flame can reach temperatures of 500 degrees.
- Blue Flame in Flames The roaring blue flame setting on a Bunsen burner produces the hottest flames.
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Answer:
in series, R1 + R2 = RT
6 + R2 = 10
R2 = 4
IN SERIES COMBINATION,
CURRENT REMAINS THE SAME.
IT = VT/RT
IT = 20/10
= 2A
I remains the same in series, hence
I1 = 2A
I2 = 2A
V1 = I R1
= 2 x 6
= 12V
V2 = I R2
= 2 X 4
= 8V
P1 = I2R
= 2 X 2 X 6
= 24 W
P2 = I2R
= 2X 2X 4
= 16 W
TOTAL POWER = P1 + P2
= 40W
Answer:
Explanation:
For image formation in objective lens
object distance u = 14 +1 = 15 mm
focal length f = 14 mm .
image distance v = ?
lens formula
Putting the values
v = 210 mm .
B )
magnification = v / u
= 210 / 15
= 14
size of image = 14 x 1.1 mm
= 15.4 mm
= 15 mm approx
C )
For final image to be at infinity , image produced by objective lens must fall at the focal point of eye piece . so objective lens's distance from the image formed by objective must be equal to focal length of eye piece that is 21 mm .
21 mm is the answer .
D )
overall magnification =
D = 25 cm , f_e = focal length of eye piece
= 14 x 250 / 21
= 166.67
= 170 ( in two significant figures )