Question

3. Write an equation of the line that passes through (-2, 8) and (4,4).

Answer 1

$y = - \frac{2}{3} x + \frac{20}{3}$

Step-by-step explanation:

y=mx+c

label your points

(-2;8). pnt2

(4;4). pnt1

$m = \frac{y2 - y1}{x2 - x1}$

$m = \frac{8 - 4}{ - 2 - 4}$

$m = \frac{ 4}{ - 6}$

$m = - \frac{2}{3}$

substitute gradient and 1 point into equation to get c

$8 = ( - \frac{2}{3} )( - 2) + c$

$8 = \frac{4}{3} + c$

$c = 8 - \frac{4}{3}$

$c = \frac{20}{3}$

Therefore the equation is

$y = - \frac{2}{3} x + \frac{20}{3}$