Question

What is the radical form of each of the given expressions?

Answer 1

Answer:

$\sf {2}^{ \frac{1}{2} } - {2}^{2} \\\sf {2}^{ \frac{2}{3} } - \sqrt[3]{ {2}^{2} } \\ \sf {3}^{ \frac{3}{2} } - \sqrt{ {3}^{3} } \\ \sf {3}^{ \frac{1}{3} } - \sqrt[3]{3}$

Answer 2

Step-by-step explanation:

$\sf \: {2}^{ \frac{1}{2} } = \sqrt{2}$

$\sf \: {2}^{ \frac{2}{3} } = \sqrt{2^3}$

$\sf \: {3}^{ \frac{3}{2} } = \sqrt[3]{ {2}^{2} }$

$\sf {3}^{ \frac{1}{3} } = \sqrt[3]{3}$