6b: impulse is change in momentum. Change in momentum p=m[v(final)-v(initial). Final velocity is zero and initial velocity is the one you calculated before impact: -15.7 since it’s going down. Now plug in numbers and you get 78.5 in the upward direction.
6c: change in momentum p=Ft. we already calculated change in momentum. So plug it into equation and solve for t. 78.5/655= 0.119 s
Apply the same idea for question 7. Hope this helped
(a) Frequency of sound wave is inversely proportional to string length.
(b) Pitch of a sound depends on the frequency while loudness depends on the amplitude of sound.
<h3>
Relationship between string length and frequency</h3>
The relationship between string length and frequency is given as;
λ = 2L
where;
- λ is wavelength
- L is length of the string
v = fλ
f = v/λ
f = v/2L
Thus, frequency of sound wave is inversely proportional to string length.
<h3>Relationship between pitch and loudness of sound</h3>
The pitch of a sound depends on the frequency while loudness of a sound depends on the amplitude of sound waves.
Learn more about pitch and loudness here: brainly.com/question/61859
Noble gasses.
alkali metals (the first column of elements), alkaline earth metals (the second column of elements), halogens (the next-to-last column of elements), and noble gases (the last column of elements).
B-Pitcher C-Catcher H-Strike I-Umpire G-Strike Zone E- Foul Ball F- Ball J- Pick-off D-Error A- Shortstop. I think (Sorry for them being out of order. I had to break them down)
Well, let’s find the initial velocity first:
Vf = Vi + at
0 = Vi - 9.8*2
0 = Vi - 19.6
Vi = 19.6 m/s
We know the final velocity is 0 because when it hits it’s peak, it’s at 0 m/s.
So now use this kinematic equation to find the final position:
Yf = Yi + Vi*t + 1/2a*t^2
Yf = 0 + 19.6(2) - 4.9(2^2)
Yf = 39.2 - 19.6
Yf = 19.6 meters
If you have any questions for how I derived anything, just lemme know. Most of the info requires thinking and imagining of the situation. I assumed you know gravity is 9.8 and you’re expected to assume velocity is 0 at peak height