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love history [14]
3 years ago
5

When forces acting on an object

Physics
2 answers:
Ksju [112]3 years ago
6 0

Answer:

it will not change

Explanation:

if the forces are of equal force then there would be no movement because one force was not stronger to move it

OLEGan [10]3 years ago
6 0
It won’t change bc it’s pushing towards each other
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1. Amplitude, loudness, volume, dynamics, and intensity are related but distinct terms. How are they different?
kupik [55]
Amplitude is a measure of the size of sound waves. It depends on the amount of energy that started the waves. Greater amplitude waves have more energy and greater intensity, so they sound louder. ... The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less.
7 0
3 years ago
Use this technique to find a formula for the intensity I of a sound, in terms of the sound level β and the reference intensity I
mezya [45]

The problem is basically asking us to find a way to find the sound intensity I, in terms dependent on the sound level and the reference intensity I_0.For this purpose we can start from the unit used in the scale logarithmic decibel, that is

\beta = 10log_{10}\frac{I}{I_0}

Where

I = Acoustic intensity on the linear scale

I_0 = Hearing threshold

Using the logarithmic properties of the exponents the above expression can be described as:

(\frac{I}{I_0})^{10} = 10^{\beta}

I = I_0 10^{\frac{\beta}{10}} \righarrow that is the expression or technique to find the intensity of sound.

8 0
3 years ago
The rubber and plastic used in protective clothing do not allow the flow of electric charge
erica [24]

Answer:

True

Explanation:

Insulators are the material that does not allow electricity to pass easily through them. The reason behind using an insulator as a protective layer on an electrical wire or appliances is that they show good resistance to electricity. That prevents us from getting an electrical shock. And rubber and plastics are good examples of the insulator.

Hence our statement is true.

6 0
3 years ago
Compute the work (in joules) required to compress a spring 3 cm
faust18 [17]

Answer:

7×160=1120kj so,1120kj=1.12j.

Explanation:

Energy is equal to force times distance,so we add all the distance and we multiply them with the total force of the spring to get the answer. However, the answer is in kilojoules so we have to change it in to joules by dividing the answer into joules by 1000..

5 0
3 years ago
Ice of mass 5 g at 0 °C melts to water at 0 °C.
amid [387]

Answer:

Q=1670J

Explanation:

Mass of ice: m=5g=0.005kg

Latent heat: lambda=3.34×10⁵J/kg

Heat received by ice: Q=m×lambda

Q=0.005×3.34×10⁵=5×334=1670J

5 0
3 years ago
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