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Varvara68 [4.7K]
1 year ago
12

Which is an equation of the line that goes through the points (-4,7) and (-4,11)​

Mathematics
1 answer:
Korvikt [17]1 year ago
4 0

Answer:

it's a answer!!

Step-by-step explanation:

ITS AN ANSWER BECAUSE IT CAN BE! THATS WHY! BLAH BLAH BLAH! I do not say blah blah blah

You might be interested in
2.35729166667 Written as a whole number?
Mama L [17]

hey it can be written as whole no

3 0
2 years ago
Andrew is 61 years. Erica is 31 years old. how many years ago was Andrew’s age 4 times Erica’s age
kozerog [31]

Answer:

21 Years Ago

Step-by-step explanation:

61 - 21 = 40

31 - 21 = 10

40/10 = 4

4 0
2 years ago
What are the domain and range of the function below?
jekas [21]

Answer:

Domain: all real numbers

Range: all real numbers greater than or equal to -2

Step-by-step explanation:

The domain is the set of x-coordinates.

It is the set of real numbers since x can be any real number.

The range is the set of y-coordinates.

The minimum value for y is -2. y can be -2 or any real number greater than -2.

Answer:

Domain: all real numbers

Range: all real numbers greater than or equal to -2

6 0
3 years ago
Read 2 more answers
Pls, help me with this math question
olya-2409 [2.1K]

Answer:

Perimeter \sqrt{26}+\sqrt{5}+\sqrt{10}+\sqrt{17} units.  Area 12 square units.

Step-by-step explanation:

Perimeter: total distance around the figure.

Distance Formula:  the distance between points \left(x_1,y_1\right) \text{ and } \left(x_2,y_2\right) is

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

AB=\sqrt{(6-1)^2+(2-1)^2}=\sqrt{25+1}=\sqrt{26}

BC=\sqrt{(5-6)^2+(4-2)^2}=\sqrt{1+4}=\sqrt{5}CD=\sqrt{(2-5)^2+(5-4)^2}=\sqrt{9+1}=\sqrt{10}DA=\sqrt{(1-2)^2+(1-5)^2}=\sqrt{1+16}=\sqrt{17}

The perimeter is the sum of all those segment lengths.

One way to find the area of the figure is to surround it with a rectangle, insert some lines so that the areas you do not want can be found and subtracted from the rectangle's area.  (See attached image.)

The area of the large rectangle around the figure is 5 x 4 = 20 square units.

The triangles have areas 1/2 (base) (height):

A. (1/2)(1)(4) = 2 square units

B. (1/2)(3)(1) = 1.5 square units

D. (1/2)(1)(2) = 1 square unit

E. (1/2)(5)(1) = 2.5 square units

Square C.  (1)(1) = 1 square unit

Total of all the area you don't want to include:

2 + 1.5 + 1 + 2.5 + 1 = 8 square units

Subtract 8 from the surrounding rectangle's area of 20, and you get the area of the figure is 20 - 8 = 12 square units.

4 0
3 years ago
1. Solve for x. Show each step of the solution<br> 4.5(8 - x) + 36 = 102 - 2.5(3x + 24)
Vladimir [108]
36-4.5x+36=102-7.5x-60
72-4.5x=42-7.5x
72+3.5x=42
3.5x=-30
x=8.57
7 0
3 years ago
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