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Make y the subject :
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y - 3 = 4(x + 8)
y - 3 = 4x + 32 // Apply distributive property
y = 4x + 35 // Add 3 to both sides
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Identify Slope :
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Slope = 4
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Find a point on the line :
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When x = 0,
y = 4(0) + 35 // Sub x = 0 into the equation
y = 35 // Combine like terms
Point = (0, 35)
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Answers :
(a) Slope = 4
(b) One point on the line is (0, 35)
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Answer:
see explanation
Step-by-step explanation:
(a)
OC = OB ( both radii of the circle )
Thus Δ BOC is isosceles with congruent base angles.
∠ BOC = ∠ BCO = 50°
(b)
∠ ACB = 90° ( angle in a semicircle ), then
∠ ACO = 90° - 50° = 40°
OA = OC ( both radii of the circle )
Thus Δ ACO is isosceles with congruent base angles.
∠ BAC = ∠ ACO = 40°
Step-by-step explanation:
BE/BC=BD/BA
tHE TWO SIMILAR TRIANGLES ARE BED AND BC. tHE PROPORTION ABOVE REPRESENTS USE OF THE TWO SIMILAR TRIANGLES.
4/(4 + 10) = 5/(5+X) Cross Multiply
4(5+x) = 5(4+10)m
20 +4x=20 +50 subtract 20 from both sides
4x = 50 divide by 4
x =12.5
Answer:
B. c= -c+2
Step-by-step explanation:
A. ...................
It has infinitely many solutions as the equation is correct for any value of c.
B. ...................
- c= -c+2
- c+c= 2
- 2c = 2
- c = 2/2
- c= 1
It has one solution only
C. ...................
- c+2=c-2
- c-c= -2 - 2
- 0 = -4
It has no solution as this equation is incorrect
D. ...................
It has no solution as this equation is incorrect
Answer:
The interval [32.6 cm, 45.8 cm]
Step-by-step explanation:
According with the <em>68–95–99.7 rule for the Normal distribution:</em> If 
is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval
![\large [\bar x - s, \bar x +s]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x%20-%20s%2C%20%5Cbar%20x%20%2Bs%5D)
around 95% of the data must fall in the interval
![\large [\bar x -2s, \bar x +2s]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x%20-2s%2C%20%5Cbar%20x%20%2B2s%5D)
around 99.7% of the data must fall in the interval
![\large [\bar x -3s, \bar x +3s]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x%20-3s%2C%20%5Cbar%20x%20%2B3s%5D)
So, the range of lengths that covers almost all the data (99.7%) is the interval
[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]
<em>This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%</em>
