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timurjin [86]
2 years ago
13

Jacob says that 4 divided by 1/3 = 12 and 4 divided by 2/3 = 6 whats the reasoning

Mathematics
1 answer:
Citrus2011 [14]2 years ago
5 0

Answer:

Keep flip change as

4/1 / 1/3=4/1 *3/1=12

4/1 / 2/3 = 4/1*3/2= 12/2=6

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Please please please help me quick!!!!!!!!!!!
geniusboy [140]
I not that good with math but I would say C.
3 0
3 years ago
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A rubber ball is dropped onto a hard surface from a height of 9 feet, and it bounces up and down. At each bounce it rises to 80%
8_murik_8 [283]
There are 12 inches in a foot, so 9ft = 108in. Also, 80% = 0.8. Therefore the formula is: h(n) = 108 * 0.8^n. To find the bounce height after 10 bounces, substitute n=10 into the equation: h(n) = 108 * 0.8^10 = 11.60in (2.d.p.). Finally to find how many bounces happen before the height is less than one inch, substitute h(n) = 1, then rearrage with logarithms to solve for the power, x: 108 * 0.8^x = 1; 0.8^x = 1/108; Ln(0.8^x) = ln(1/108); xln(0.8) = ln(1\108); x = ln(1/108) / ln(0.8) = -4.682 / -0.223 = 21 bounces
4 0
2 years ago
100 POINTS ANSWER HURRY
choli [55]
X-3y=18
X always has a 1 in front of it so
1x-3y=18
-1x      -1x         You will have to get -3y by its self.
-3y=-1x + 18      when you move 1x over the = it turns into a -1x
/-3    /-3      /-3      divided everything by -3 to get y by its self
Y= 1/3 - 6            and that is you answer
4 0
2 years ago
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It costs $70 for 50 tickets. How much does each ticket cost?
liberstina [14]
1 dollar and 40 cents
5 0
2 years ago
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In a certain country the life expectancy for women in 1990 was 45 and in 2000 it was 85?years. Assuming that life expectancy bet
Darya [45]

Answer:

49145 years

Step-by-step explanation:

In a certain country the life expectancy for women in 1990 was 45 and in 2000 it was 85?years.

Assuming that life expectancy between 2000 and 2100 increases by the same percentage as it did between 1900 and 2000,what will life expectancy be for women in 2100?

In 10 years, the expectancy increased by 85/45 = 17/9

between 2000 and 2100, it will increas by 10 time 10 years, so expected expectancy is  85*(\frac{85}{45})^{10} = 49145  years

4 0
3 years ago
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