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4 years ago

What led to Galileo's discovery of a way to measure small amounts of time more accurately?

Physics

2 answers:

Natasha_Volkova [10]4 years ago

7 0

Answer:

he proved that not all heavenly bodies revolve around earth.

Explanation:

DedPeter [7]4 years ago

5 0

Galileo saw a pendulum and wondered why it took the same amount of time moving back and froth. He noted the time the pendulum took it to hold it to his heart. He noted his heart beats as a reference of the small times the pendulum took to reach a particular distance.

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Pls help me, sooner than later

Firlakuza [10]

The forces on the mass on the table are balanced because it moves at constant speed. The force to the right is 2mg, the force to the left must also be 2mg. The weight on the left is 1mg so the friction force on the mass on the table is also 1mg to the left.

6 0

3 years ago

Be sure to answer all parts. Assume the diameter of a neutral helium atom is 1.40 × 102 pm. Suppose that we could line up helium

ss7ja [257]

Answer:

The number of atoms are $1.86\times10^{8}$ .

Explanation:

Given that,

Diameter $D = 1.40\times10^{2}\ pm$

$D=1.40\times10^{2}\times10^{-12}\ m$

Distance = 2.60 cm

We calculate the number of atoms

Using formula of numbers of atoms

$Number\ of\ atoms =\dfrac{2.60\times10^{-2}}{1.40\times10^{2}\times10^{-12}}$

$Number\of\atoms =1.86\times10^{8}$

Hence, The number of atoms are $1.86\times10^{8}$ .

8 0

3 years ago

Jack (mass 52.0 kg ) is sliding due east with speed 8.00 m/s on the surface of a frozen pond. he collides with jill (mass 49.0 k

dybincka [34]

We must write down laws of conservation of momenta and energy.
For the law of conservation of momenta will we will use two axes. One will be x-axis that will correspond to the east, and the other one will be y-axis corresponding to the north. Jack will be marked as 1 and Jill will be marked as 2.
Law of conservation of energy:
$\frac{m_1v_1^2}{2}=\frac{m_1v'_1^2}{2}+ \frac{m_2v_2^2}{2}\\
m_2v_2^2=m_1v_1^2-m_1v_1'^2\\
v_2=\sqrt{\frac{m_1v_1^2-m_1v_1'^2}{m_2}$
This will give us Jill's velocity after the colision.
$v_2=6.43\frac{m}{s}$
Law of conservation of momenta:
$x: m_1v_1=m_1v_1'cos(34)+m_2v_2cos(\theta)\\
y: 0=m_1v_1'sin(34)-m_2v_2sin(\theta)\\$
We will use the second equation to get the angle at which the Jill is traveling:
$0=m_1v_1'sin(34)-m_2v_2sin(\theta)\\
m_2v_2sin(\theta)=m_1v_1'sin(34)\\
sin(\theta)=\frac{m_1v_1'sin(34)}{m_2v_2}\\
\theta=sin^{-1}(\frac{m_1v_1'sin(34)}{m_2v_2})$
When we plug all the number we get:
$\theta=27.45^\circ$
Please note that this is the angle below the x-axis.

6 0

3 years ago

How many legs does an arachnid have??

Virty [35]

An arachnid has eight legs.

6 0

3 years ago

A 0.500-kilogram cart traveling to the right on a horizontal, frictionless surface at 2.20 meters per second collides head on wi

babunello [35]

Consider the motion towards right as positive and motion towards left as negative.

m₁ = mass of the cart moving to right = 0.500 kg

v₁ = initial velocity before collision of the cart moving towards right = 2.2 m/s

m₂ = mass of cart moving to left = 0.800 kg

v₂ = initial velocity before collision of the cart moving towards left = - 1.1 m/s

initial momentum of the system of carts before the collision is given as

P₁ = m₁ v₁ + m₂ v₂

P₁ = (0.500) (2.2) + (0.800) (- 1.1)

P₁ = 0.22 kg m/s

P₂ = momentum of system of carts after collision

As per conservation of momentum,

Momentum of system of carts after collision = Momentum of system of carts before collision

P₂ = P₁

P₂ = 0.22 kg m/s

8 0

3 years ago