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3 years ago

Mga halimbawa ng metapora

Physics

2 answers:

faust18 [17]3 years ago

4 0

Answer:

UMm If i understood ide answer

Explanation:

mart [117]3 years ago

3 0

Ang isang talinghaga ay isang pigura ng pagsasalita na, para sa retorikong epekto, direktang tumutukoy sa isang bagay sa pamamagitan ng pagbanggit ng isa pa. Maaari itong magbigay ng kalinawan o makilala ang mga nakatagong pagkakatulad sa pagitan ng dalawang magkakaibang mga ideya. Ang mga talinghaga ay madalas na ihinahambing sa iba pang mga uri ng matalinhagang wika, tulad ng antithesis, hyperbole, metonymy at simile.

1. Ang kanyang mga salita ay pinutol ng mas malalim kaysa sa isang kutsilyo. Ang mga salita ay hindi natutupad sa matatalim na bagay. Sa talinghagang ito, sinabi ng isang tao ang isang bagay na nakasakit sa iba pa.

2. Nararamdaman kong dumarating ang baho ng kabiguan. Ang pagkabigo ay hindi masaya ngunit hindi ito amoy. Kaya, kapag ginamit ang talinghagang ito, nangangahulugan itong malapit na ang isa sa mga pagkabigo ng buhay.

3. Nalulunod ako sa dagat ng kalungkutan. Dito, napakalaki ng kalungkutan na nararamdaman ng tao na walang magawa, tulad ng hinihila siya sa ilalim ng tubig.

4. Dumadaan siya sa isang rollercoaster ng emosyon. Ang aming emosyon ay hindi maaaring sumakay sa isang rollercoaster. Ang talinghagang ito ay nangangahulugan lamang ng pagdaan ng isang tao sa maraming iba't ibang mga kalooban.

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Which of the following are located on a plant's leaves?

valina [46]

i think its stomata....

4 0

2 years ago

a. A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 26.7° and the angle of refracti

Diano4ka-milaya [45]

Answer:

(a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

Explanation:

Given that,

Incidence angle = 26.7°

Refraction angle = 18.3°

(a). We need to calculate the refraction of liquid

Using Snell's law

$n=\dfrac{\sin i}{\sin r}$

Put the value into the formula

$n=\dfrac{\sin 26.7}{\sin 18.3}$

$n=1.43$

We need to critical angle for the liquid when surrounded by air

Using formula of critical angle

$C=\sin^{-1}(\dfrac{1}{n})$

Put the value into the formula

$C=\sin^{-1}(\dfrac{1}{1.43})$

$C=44.37^{\circ}$

(b). Given that,

Incidence angle = 37.5°

Speed of light in mineral $v=2.17\times10^{8}\ m/s$

We need to calculate the index of refraction

Using formula of index of refraction

$n=\dfrac{c}{v}$

Put the value into the formula

$n=\dfrac{3\times10^{8}}{2.17\times10^{8}}$

$n=1.38$

We need to calculate the angle of refraction

Using Snell's law

$n=\dfrac{\sin i}{\sin r}$

$\sin r=\dfrac{\sin i}{n}$

Put the value into the formula

$\sin r=\dfrac{\sin 37.5}{1.38}$

$r=\sin^{-1}(\dfrac{\sin 37.5}{1.38})$

$r=26.17^{\circ}$

Hence, (a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

3 0

3 years ago

Read 2 more answers

Select the correct answer.

TEA [102]

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4 0

3 years ago

Read 2 more answers

A 782-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satelli

Vadim26 [7]

Answer:

a) v = 5.59x10³ m/s

b) T = 4 h

c) F = 1.92x10³ N

Explanation:

a) We can find the satellite's orbital speed by equating the centripetal force and the gravitation force as follows:

$F_{c} = F_{G}$

$\frac{mv^{2}}{r + h} = \frac{GMm}{(r + h)^{2}}$

$v = \sqrt{\frac{gr^{2}}{r+h}$

Where:

g is the gravity = 9.81 m/s²

r: is the Earth's radius = 6371 km

h: is the satellite's height = r = 6371 km

$v = \sqrt{\frac{gr^{2}}{2r}} = \sqrt{\frac{gr}{2}} = \sqrt{\frac{9.81 m/s^{2}*6.371 \cdot 10^{6} m}{2}} = 5.59 \cdot 10^{3} m/s$

b) The period of its revolution is:

$T = \frac{2\pi}{\omega} = \frac{2\pi (r + h)}{v} = \frac{2\pi (2*6.371 \cdot 10^{6} m)}{5.59 \cdot 10^{3} m/s} = 14322.07 s = 4 h$

c) The gravitational force acting on it is given by:

$F = \frac{GMm}{(r + h)^{2}}$

Where:

M is the Earth's mass = 5.97x10²⁴ kg

m is the satellite's mass = 782 kg

G is the gravitational constant = 6.67x10⁻¹¹ Nm²kg⁻²

$F = \frac{GMm}{(r + h)^{2}} = \frac{6.67 \cdot 10^{-11} Nm^{2}kg^{-2}*5.97 \cdot 10^{24} kg*782 kg}{(2*6.371 \cdot 10^{6} m)^{2}} = 1.92 \cdot 10^{3} N$

I hope it helps you!

3 0

4 years ago

The half life of a species that undergoes zero order kinetics is ____ and the rate constant has units of ____.

-BARSIC- [3]

The reaction of the half-life is a description of the needed time for the reactant to deplete.In the first order reactions formula, k is considered as the first order rate constant whose unit is denoted as 1/s. Hope this helps.

6 0

4 years ago

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