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o-na [289]
3 years ago
6

Imagine no girls awnser this question ://

Physics
2 answers:
alina1380 [7]3 years ago
4 0
Wdym I am answering rn
Nat2105 [25]3 years ago
3 0

Answer:

im confused

Explanation:

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Which changes would most likely limit the growth of a plant-eating animal population
BabaBlast [244]
Probably the changes in environment....
8 0
3 years ago
Take one jar with salt water and another with pure water .put an egg into both jars. In which the jar egg floated over the liqui
DanielleElmas [232]

Answer:

if the which coduct salt has more density so the egg floats .

Explanation:

8 0
3 years ago
If the 0.09-mm-diameter tungsten filament in a light bulb is to have a resistance of 0.11 Ω at 20∘C, how long should it be?
skad [1K]

Answer:

Length L=0.0125 m

Explanation:

Given data

Resistance R=0.11Ω

Temperature T=20°C

Resistivity of tungsten at 20°C p=5.6×10⁻⁸Ω.m²

Radius of filament r=0.09/2 =0.045 mm =0.045×10⁻³m

To find

Length of filament L

Solution

The Cross section of area of filament is given as:

A=\pi r^{2}\\ A=\pi (0.045*10^{-3})^{2}\\A=6.3585*10^{-9}m^{2}

The Resistance of a material is given as:

R=p\frac{L}{A} \\L=\frac{AR}{p}\\ L=\frac{(6.3585*10^{-9})(0.11)}{5.6*10^{-8}}\\L=0.125m

6 0
3 years ago
a hockey player makes a slap shot exerting a constant force of 25.0 N on the puck for 0.16 seconds. With is the magnitude of the
Sav [38]

Impulse = (force) x (time the force is applied)

Impulse = (25 N) x (0.16 sec)

<em>Impulse = 4 Newton-seconds</em>

8 0
3 years ago
Read 2 more answers
Consider a rifle, which has a mass of 2.44 kg and a bullet which has a mass of 150 grams and is loaded in the firing chamber.Whe
svetlana [45]

Answer:

a. 0 kgm/s

b. 0 kgm/s

c. 66 kgm/s

d. -66 kgm/s

e. 0 kgm/s

f. -27.05 m/s

g. 173.68 N

h. 12.58 m/s

i. 0.772 m

j. 14487 J

Explanation:

150 g = 0.15 kg

a. Before the bullet is fired, both rifle and the bullet has no motion. Therefore, their velocity are 0, and so are their momentum.

b. The combination is also 0 here since the bullet and the rifle have no velocity before firing.

c. After the bullet is fired, the momentum is:

0.15*440 = 66 kgm/s

d. As there's no external force, momentum should be conserved. That means the total momentum of both the bullet and the rifle is 0 after firing. That means the momentum of the rifle is equal and opposite of the bullet, which is -66kgm/s

e. 0 according to law of momentum conservation.

f. Velocity of the rifle is its momentum divided by mass

v = -66 / 2.44 = -27.05 m/s

g. The average force would be the momentum divided by the time

f = -66 / 0.38 = 173.68 N

h. According the momentum conservation the bullet-block system would have the same momentum as before, which is 66kgm/s. As the total mass of the bullet-block is 5.1 + 0.15 = 5.25. The velocity of the combination right after the impact is

66 / 5.25 = 12.58 m/s

i. The normal force and also friction force due to sliding is

F_f = N\mu = Mg\mu = 5.25*9.81*0.83 = 42.75N

According to law of energy conservation, the initial kinetic energy will soon be transformed to work done by this friction force along a distance d:

W = K_e

dF_f = 0.5Mv_0^2

d = \frac{Mv_0^2}{2F_f} = \frac{5.25*12.58^2}{2*42.75} = 0.772 m

j.Kinetic energy of the bullet before the impact:

K_b = 0.5*m_bv_b^2 = 0.5*0.15*440^2 = 14520 J

Kinetic energy of the block-bullet system after the impact:

K_e = 0.5Mv_0^2 = 0.5 * 5.25*12.58^2 = 33 J

So 14520 - 33 = 14487 J was lost during the lodging process.

3 0
3 years ago
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