Answer:
Hi there! Please find the answer below.
Explanation:
The program below demonstrates how each of the requirements can be coded in a simple Python script. To copy the array, we can use the copy() method of the array. To calculate the diff, we can use a few different techniques, so I have implemented it using a loop over the arrays and just storing and displaying the difference in the 2 arrays.
new_string.py
def add_test_score(score):
test_score.append(score);
contact_hash = {}
test_score = []
print("Enter 5 test scores: ");
for x in range(0, 5):
input_string = input("Enter test score " + str(x + 1) + ": ")
add_test_score(int(input_string));
print(test_score);
test_score_copy = test_score.copy();
for e in test_score_copy:
if e < 60:
test_score_copy[test_score_copy.index(e)] += 10;
diff = [];
for e in test_score:
print(test_score[test_score.index(e)]);
print(test_score_copy[test_score.index(e)]);
if not test_score[test_score.index(e)] == test_score_copy[test_score.index(e)]:
diff.append(e);
print(diff);
Profile? Perhaps... If you go on social media sites like Facebook it's typically on your profile, right?
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Answer:
It is bit { measurement used to quantify computer data. }
Answer:
class OddNumber
{
public static void main(String args[])
{
int n = 1000; //Store 1000 in Variable n typed integer
System.out.print("Odd Numbers from 1 to 1000 are:"); // Print headline of output window
for (int i = 1; i <= n; i++) //For loop to go through each number till end
{
if (i % 2 != 0) //check if number is even or odd.Not divisible by 2 without reminder means it is odd number
{
System.out.print(i + " "); //print odd numbers
}
}
}
}
