With sexual reproduction a sperm coming from the male must unite with the female egg. Both are needed for this kind of reproduction, and an offspring CAN'T be formed without both. Unlike asexual reproduction, the offspring of a mammal reproducing sexually is DIFFERENT from both parents, since the offspring is a combination of both the mother and the father.
An easy to remember example I use when thinking about what sexual reproduction is:
the formation of a human child. A mother with her egg and the father with the sperm is BOTH needed. If you think about siblings that come from the same parents (and therefore same gene pool) they are not all exactly identical to each other. Although they may have similar features, they look different and are NOT genetically identical
Therefor for your question the answer is D.
Hope this helped!
I don't know how specific you need to get for this question. The basic answer would be the mitochondria as it is where the Krebs Cycle, the Electron Transport Chain, and Chemiosmosis (also referred to as oxidative phosphorylation) all occur. Chemiosmosis is where the majority of ATP is produced during cellular respiration, and it primarily occurs in the matrix of the mitochondria as protons move down the gradient through ATP Synthetase channels.
1. is B Horst
2. is A Graben
We can use the formula for orbital time period:
T² = (4π²/GM)a³; where T is in Earth years, a is distance from sun in AU, M is the solar mass (1 for the sun), G is the gravitational constant.
In the given units, 4π²/G = 1
T² = 0.66³
T = 0.536 Earth years = 195.71 Earth days
Answer:
See the answer below
Explanation:
a) The mode of inheritance of the bar mutant is X-linked and dominant.
Assuming that barness is represented by the allele B.
Bar female = 
or 
Wild type male = 
Bar female x wild type male:
x
All of the F1 flies are bar because a single B allele is required for the trait to be expressed.
Bar male x wildtype female
x 
All the female offspring are barred while all the males are wildtype barred resulting in a 50/50 (857/905 is approximately 50/50) ratio of barred/wildtype offspring.
b) Genotypes of each of the cross above, including the parents and the F1 generations.
1. x
2. x
