Well if you had either the velocity or distance traveled i could tell you. But since you haven't all i can say for sure is that the water slowed the bullet down to 13m/s so lets say you knew the distance you would calculate how many meters it traveled and you would have your answer because in this situation, meters (height) =how many seconds spent going into the air.
Because a nuclear meltdown can be caused if systems fail.
Answer:
4.41 m/s^2
Explanation:
(v_f)^2 - (v_i)^2 = 2a * change in distance
(21)^2 - (0)^2 = 2a * 50
a = (21^2)/(2*50)
a = 4.41 m/s^2
Assuming that the collision is inelastic that is they are stuck together after the collision, momentum is conserved. We can determine the final velocity of the final mass as follows:
m1v1 + m2v2 = m3v3
100(4) + (200)(-3) = (300)v3
v3 = -0.6667 m/s
Therefore, the final mass moves at 0.6667 m/s to the left.
What are the options as the question would make a lot more sense?
