Answer:
13. 2.60 L.
14. 2.40 L.
Explanation:
We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
If n and T are constant, and have different values of P and V:
(P₁V₁) = (P₂V₂)
<em>13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the pressure is increased to 1.25 atm.</em>
P₁ = 0.755 atm, V₁ = 4.31 L.
P₂= 1.25 atm, V₂ = ??? L.
∴ V₂ = (P₁V₁)/(P₂) = (0.755 atm)(4.31 L)/(1.25 atm) = 2.60 L.
<em>14. 600.0 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at 2.00 at
m.</em>
P₁ = 8.0 atm, V₁ = 600.0 mL.
P₂= 2.0 atm, V₂ = ??? L.
∴ V₂ = (P₁V₁)/(P₂) = (8.0 atm)(600.0 mL)/(2.0 atm) = 2400/0 mL = 2.40 L.
