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2 years ago

PLEASE ANSWER FOR EXTRA POINTS ⭐️⭐️⭐️ GIVE BRAINLIST

Mathematics

2 answers:

Andrei [34K]2 years ago

7 0

Answer:

D. all real numbers

Step-by-step explanation:

The domain is all the x's on a graph or that are permitted in an equation (if you have an equation instead of a graph)

If there is nothing on the graph to indicate the graph is a segment (endpoints that are either closed or open) or has other holes in it (literally a point on the line that is open) then the domain for a linear function (a line) is always all real numbers. The same is true for all of the above for the range as well, except the range is all the y's

Ksenya-84 [330]2 years ago

7 0

Answer is D. all real numbers

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A rucksack can hold a maximum of 3 kg.

devlian [24]

Answer:

4 textbooks

Step-by-step explanation:

3 kg = 3000 g

3000 ÷ 650 = 4.61......

Maximum number is 4 as 0.61... book being carried is not possible

Hope this helped and brainliest please

4 0

2 years ago

Read 2 more answers

Consider that x=5 and y=7. Is the sum of x + y rational, irrational, or neither irrational nor rational!

nasty-shy [4]

The sum of y+x, or 5+7, is rational. This is because each integer(non fraction/decimal)is rational, it is also rational.

5 0

3 years ago

There are 10 rolls of film in a box and 3 are defective. two rolls are selected without replacement. what is the probability of

german

P(picking one defective) = 3/10
P(picking a 2nd defective) = 2/9

P(1 and 2 defective) = 3/10 x 2/9 = 6/90 = 0.066

Second method using combination:
³C₂ / ¹⁰C₂ = 1/15 = 0.066

4 0

3 years ago

The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes

saul85 [17]

Answer:

a)0.08 , b)0.4 , C) i)0.84 , ii)0.56

Step-by-step explanation:

Given data

P(A) = professor arrives on time

P(A) = 0.8

P(B) = Student aarive on time

P(B) = 0.6

According to the question A & B are Independent

P(A∩B) = P(A) . P(B)

Therefore

${A}'$ & ${B}'$ is also independent

${A}'$ = 1-0.8 = 0.2

${B}'$ = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B') (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

$P(\frac{B'}{A})$ = $\frac{P(B'\cap A)}{P(A)}$ = $\frac{0.4\times 0.8}{0.8}$ = 0.4

Part c)

Assume the events are not independent

Given Data

P $(\frac{{A}'}{{B}'})$ = 0.4

= $\frac{P({A}'\cap {B}')}{P({B}')}$ = 0.4

$P$ $({A}'\cap {B}')$ = 0.4 x P $({B}')$

= 0.4 x 0.4 = 0.16

$P({A}'\cap {B}')$ = 0.16

The probability that at least one of them is on time

$P(A\cup B)$ = 1- $P({A}'\cap {B}')$

= 1 - 0.16 = 0.84

ii)The probability that they are both on time

P $(A\cap B)$ = 1 - $P({A}'\cup {B}')$ = 1 - $[P({A}')+P({B}') - P({A}'\cap {B}')]$

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0

2 years ago

Item 18 you and your friend are selling tickets to a charity event. you sell 7 adult tickets and 16 student tickets for $120. yo

quester [9]

Answer:

Step-by-step explanation:

The two purchases can be written in terms of the cost of an adult ticket (a) and the cost of a student ticket (s):

7a +16s = 120 . . . . . . . . price for the first purchase

13a +9s = 140 . . . . . . . . price for the second purchase

Using Cramer's rule, the value of s can be found as ...

s = (120·13 -140·7)/(16·13 -9·7) = 580/145 = 4

The cost of a student ticket is $4.

_____

<em>Comment on Cramer's Rule</em>

Cramer's rule is particularly useful for systems that don't have "nice" numbers that would make substitution or elimination easy methods to use. If you locate the numbers in the equation, you can see the X-patterns that are used to compute the numerator and denominator differences.

The value of a is (16·140 -9·120)/(same denominator) = 1160/145 = 8. I wanted to show you these numbers so you could see the numerator X-pattern for the first variable.

Of course, graphical methods can be quick and easy, too.

8 0

3 years ago