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BabaBlast [244]
3 years ago
10

What is the slope of the line? (0,2) (4, -1)

Mathematics
1 answer:
Ad libitum [116K]3 years ago
3 0
(-3,4) djdjfk food of
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9:45 on Tuesday Questions
LenaWriter [7]

Answer:  -2x + 5y = 8

Step-by-step explanation:

Since the lines must be parallel, the slopes must be the same, so keep the coefficients of x and y

Substitute the values of x and y from the given coordinate  (6,4) to find the new constant, b, the y-intercept.

-2x + 5y = b

-2(6) + 5(4) = b

-12 + 20 = b

8 = b

Rewrite the original equation substituting the new b for the original -15

-2x + 5y = 8

5 0
3 years ago
Change 3 radians to degree measures
uysha [10]

<span>π radians =180∘</span>

1 radian = tex] \frac{180°}{ \pi} [/tex]π

3 radians = \frac{540°}{ \pi}

7 0
3 years ago
Read 2 more answers
Julio ​says, "If you subtract 16 from my number and multiply the difference by −6​, the result is −138​." What is Julio​'s ​numb
omeli [17]

Answer:

-7

Step-by-step explanation:

use X to represent the unknown number

(x-16) -6=-138

-138/6= -23

(x-16)=-23

add 16 to both sides

x= -7

Julio's number is -7

you can also plug it back into the formula to prove it is right

3 0
3 years ago
The sales tax for an item was $32.80 and it cost $410 before tax
Darya [45]

Answer:

do you have any answers to choose from?

8 0
3 years ago
75 points. Will give certified if work is shown and the answer is correct.
Svetach [21]
Volume of the first dwarf planet (r₁ = 832 mi):

V_1=\dfrac{4}{3}\cdot\pi\cdot r_1^3=\dfrac{4}{3}\cdot\pi\cdot 832^3=\dfrac{2303721472}{3}\pi\approx7.679\cdot10^8\pi\,\text{mi}^3

Volume of the second dwarf planet (r₂ = 829 mi):

V_2=\dfrac{4}{3}\cdot\pi\cdot r_2^3=\dfrac{4}{3}\cdot\pi\cdot 829^3=\dfrac{2278891156}{3}\pi\approx7.5963\cdot10^8\pi\,\text{mi}^3

So difference between the volumes is:

V_1-V_2\approx7.679\cdot10^8\pi-7.5963\cdot10^8\pi=0.0827\cdot10^8\pi=\boxed{8270000\pi\,\text{mi}^3}

or if we want exact value (we use (a³-b³) = (a-b)(a²+ab+b²) ):

V_1-V_2=\dfrac{4}{3}\cdot\pi\cdot r_1^3-\dfrac{4}{3}\cdot\pi\cdot r_2^3=\dfrac{4}{3}\pi(r_1^3-r_2^3)=\dfrac{4}{3}\pi(832^3-829^3)=\\\\\\=\dfrac{4}{3}\pi(832-829)(832^2+832\cdot829+829^2)=\\\\\\=\dfrac{4}{3}\pi\cdot3(692224+689728+687241)=4\pi\cdot2069193=\boxed{8276772\pi\,\text{mi}^3}
3 0
3 years ago
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