Look up on desmos it will give the correct answer
Answer:
C - He substituted incorrectly when calculating the constant of variation.
Answer:
3 seconds
Step-by-step explanation:
You want to set h(t)=3, then take the root such that t≠0. You would have:
3=3+48t−16t^2
Let's solve your equation step-by-step.
3=3+48t−16t2
Step 1: Simplify both sides of the equation.
3=−16t2+48t+3
Step 2: Subtract -16t^2+48t+3 from both sides.
3−(−16t2+48t+3)=−16t2+48t+3−(−16t2+48t+3)
16t2−48t=0
Step 3: Factor left side of equation.
16t(t−3)=0
Step 4: Set factors equal to 0.
16t=0 or t−3=0
t=0 or t=3
3 makes more sense than 0 because the ball can't have been in the air for 0 seconds.
So the ball was in the air for 3 seconds.
Answer: The difference cannot be found because the indices of the radicals are not the same.
Step-by-step explanation:
To find the difference you need to subtract the radicals. But it is important ot remember the following: To make the subtraction of radicals, the indices and the radicand must be the same.
In this case you have these radicals:
![\sqrt[ {8ab}^{3} ]{{ac}^{2} }- \sqrt[ {14ab}^{3}]{{ac}^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B%20%7B8ab%7D%5E%7B3%7D%20%5D%7B%7Bac%7D%5E%7B2%7D%20%7D-%20%5Csqrt%5B%20%7B14ab%7D%5E%7B3%7D%5D%7B%7Bac%7D%5E%7B2%7D%20%7D)
You can observe that the radicands are the same, but their indices are not the same.
Therefore, since the indices are different you cannot subtract these radicals.
