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kirill115 [55]
3 years ago
11

napthalene combustion can be used to calibrate the heat capacity of a bomb calorimeter The heat of combustion of naphthalene is

-40.1kj/g. When .8210g of naphthalene was burned in a calorimeter containing 1,000g of water, a temperature rise of 4.21C was observed. What is the heat capacity?
Chemistry
1 answer:
erica [24]3 years ago
7 0

A bomb calorimeter with a heat capacity of 3.63 kJ/°C experiences a temperature rise of 4.21 °C when .8210 g of naphthalene is burned.

The combustion of naphthalene is used to calibrate the heat capacity of a bomb calorimeter.

<h3>What is a bomb calorimeter?</h3>

It is a device used to measure the change in the internal energy of a reaction.

To determine the heat capacity of the calorimeter (C), we need to follow a series of steps.

  • Step 1: Calculate the heat released by the combustion.

The heat of combustion of naphthalene is -40.1kJ/g and .8210g were burned.

Qcomb = -40.1kJ/g × .8210g = -32.9 kJ

  • Step 2: Determine the heat absorbed by the bomb calorimeter.

According to the law of conservation of energy, the sum of the heat released by the combustion and the heat absorbed by the bomb calorimeter is zero.

Qcomb + Qbomb = 0

Qbomb = -Qcomb = 32.9 kJ

  • Step 3: Calculate the heat capacity of the bomb calorimeter.

32.9 kJ were absorbed, part by the calorimeter itself and part by the 1,000 g (m) of water, whose specific heat capacity (c) is 4.18 J/g°C.

A temperature rise (ΔT) of 4.21 °C is observed. We can determine the heat capacity of the bomb calorimeter (C) using the following expression.

Qbomb = Qcal + Qwater

32.9 kJ = C × ΔT + c × m × ΔT

32.9 kJ = C × 4.21 °C + (4.18 × 10⁻³ kJ/g.°C) × 1,000 g × 4.21 °C

C = 3.63 kJ/°C

A bomb calorimeter with a heat capacity of 3.63 kJ/°C experiences a temperature rise of 4.21 °C when .8210 g of naphthalene is burned.

Learn more about the bomb calorimeter here: brainly.com/question/9360310

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Oxidation of a 24-carbon fatty acid would require ELEVEN (11) rounds of beta-oxidation and TWELVE (12) rounds of the Krebs cycle. It is part of cellular respiration.

<h3>The Krebs cycle and cellular respiration</h3>

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3 0
2 years ago
How to find weight with volume and density ​
stira [4]

Answer:

Explanation:

Look up the density of the material the object is made of in kg/m³.

Measure the volume of the object in m³.

Multiply the density by the volume.

You will then have the mass of the object in kg.

5 0
3 years ago
A 20g sample of iron at a temperature of 120oC is placed into a container of water. There are 300 milliliters of water in the co
galben [10]

Answer:

30.63 °C will be the final temperature of the water.

Explanation:

Heat lost by iron will be equal to heat gained by the water

-Q_1=Q_2

Mass of iron = m_1=20 g

Specific heat capacity of iron = c_1=0.444 J/g^oC

Initial temperature of the iron = T_1=120^oC

Final temperature = T_2=T

Q_1=m_1c_1\times (T-T_1)

Volume of water = 300 ml

Density of water = 1 g/mL

Mass of water= m_2=300 mL\times 1 g/mL = 300 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=30^oC

Final temperature of water = T_2=T

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

we get, T =  30.63°C

30.63 °C will be the final temperature of the water.

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How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 30.6 moles of water vapor?
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H₂ + CO₂ ⇄ CO + H₂O

1 mol H₂ - 1 mol H₂O
x mol H₂ - 30.6 mol H₂O

x=30.6*1/1=30.6 mol  (<span>theoretically)</span>
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What is mass in science?
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Its like weight but not. mass is the amount of matter in a substance.
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