Question

Two protons and two neutrons are released as a result of this reaction. Superscript 222 subscript 86. Rn Right arrow superscript 218 subscript 84. Po ? Which particle is released? one alpha particle two beta particles one alpha and one beta particle one high-energy photon.

Answer 1

The particle released in the reaction has been an alpha particle. Thus, option A is correct.

The release of protons and neutrons in a reaction has been nuclear reactions. The reactions results in the change in the atomic mass of the atom, with the formation of new atom. The extra mass has been released in the form of energy.

The release from the given reaction has been:

$\rm ^{222}_{66}Rn\;\rightarrow\;^{218}_{84}Po\;+\;^A_ZX$

Where, X has been the particles that has been released with the nuclear reaction. The superscript A has been the Mass of particle, and subscript Z has been the atomic number.

According to the law of conservation, the mass has been constant on both the product and the reactant side. Thus, the mass and atomic number of eliminated particles has been given as:

$\rm 222=218+A\\A=222-218\\A=4$

The atomic mass of the particle has been 4.

$\rm 86=84+Z\\Z=86-84\\Z=2$

The atomic number of the particle has been 2.

The element with atomic mass 4, and atomic number 2 has been the Helium particles, $\rm ^4_2He$. It has been an alpha particle. Thus, the particle released in the reaction has been an alpha particle. Thus, option A is correct.

For more information about the particles released, refer to the link:

brainly.com/question/2600896