Question

Tooth enamel is ca5(po4)3(oh). calculate the percent composition of the elements present.

Answer 1

We shall find the molar mass first.  
Ca5(PO4)3(OH) = (40 * 5) + 3 (31 + 4(16)) + 16 + 1 = 200 + 285 + 17 = 485 + 17 = 502. 
Percent of Calcium = 200/ 502 * 100 = 39.8%
 Percent of Phosphorus = 91/502 * 100 = 18.1%
 Percent of Hydrogen = 1/502 * 100 = 0.19%
 Percent of Oxygen = 100 - (39.8 + 18.1 + 0.19) = 41.91%

Answer 2

Tooth enamel is hydroxyapatite with the chemical formula Ca₅(Po₄)₃OH. The percent composition of the elements are:

Ca - 7.35%

Po - 92.02%

O - 0.59%

H - 0.04%

FURTHER EXPLANATION

Mass percent or percent composition is the ratio of an element's mass to the mass of the compound. It is mathematically expressed as:

$mass \ \% \ of \ X = \frac{mass \ of X}{mass \ of \ compound} \times 100$

To determine the percent composition of each element in tooth enamel, we first get the mass of the compound:

$mass \ of \ compound \ = (5 \times 40.078) +(12 \times 209) + \ 15.999 +1.008\\\\\boxed {mass \ of \ compound = 2725.397 \ g}$

To get the percentage composition, use the first equation and plug in the appropriate values:

• %Ca

$\% Ca= \frac{5 \times 40.078 \ u}{2725.397 u} \times 100\\\\\boxed {\% Ca= 7.35\%}$

• %Po

$\% Po= \frac{12 \times 209 \ u}{2725.397 u} \times 100\\\\\boxed {\% Po=92.02\%}$

• %O

$\% O= \frac{15.999\ u}{2725.397 u} \times 100\\\boxed {\% O=0.59\%}$

• %H

$\% H= \frac{1.008\ u}{2725.397 u} \times 100\\\boxed {\% O=0.04\%}$

LEARN MORE

• Learn more about Mass Percentage  brainly.com/question/4213901
• Learn more about Empirical formula brainly.com/question/8516072

Keywords: tooth enamel, percent composition