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user100 [1]
2 years ago
5

What is the smallest 4 digit number with 4 different digits.

Mathematics
1 answer:
Mnenie [13.5K]2 years ago
5 0
Your answer would be 1234
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Consider a triangle ABC like the one below. Suppose that a=51, b=16, and A=108. (The figure is not drawn to scale.) Solve the tr
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Answer:

B = 17.4°

C = 54.6°

c=43.7

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Explain how you can tell how well a linear or exponential fits a set of data
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The coordinates that you record is an example of data from the graph I think
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Which is the side length of a cube with a volume of 2744 cm3?<br><br> Please help
Elis [28]
\sf~V=a^3

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\sf2744=a^3

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\sf~a=\sqrt[3]{2744}

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3 years ago
Read 2 more answers
The Jacksons sublet their summer cottage during the winter and spring months. For each month they receive 72% of their monthly m
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Answer:

7,560

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2 years ago
PLEASE PLEASE ANSWER THIS FOR ME I REALLY NEED TO UNDERSTAND IT
dexar [7]

Answer:

See answers below for explanations (answers are in bold)

Step-by-step explanation:

<u>Problem 1 (Top left):</u>

Assuming that the shape is an ellipse, we will use the formula A=πab where a and b are both half the major and minor axis respectively. Since a=9 and b=6, then we have A = π(9)(6) = 54π = 169.646 units^2 as our final answer

<u>Problem 2 (Top right):</u>

Again, we use the same equation as in Problem 1 but this time, a=12 and b=8, so we then have A = π(8)(12) = 96π = 301.593 units^2 as our final answer

<u>Problem 3 (Bottom left):</u>

We can make this irregular shape into a half-ellipse and a rectangle. We would find their separate areas and add them up. The area of the half-ellipse would be A=1/2πab. The value of "a" would be 13.8/2=6.9 since that's the length of the rectangle. The value of "b" would be 3.5, so that means the area of the half-ellipse would be A = 1/2(π)(6.9)(3.5) = 12.075π = 37.935 units^2.  The width and length of the rectangle are 5.4 and 13.8 respectively, so this means the area of the rectangle is 5.4*13.8 = 74.52 units^2. Combining both areas, we get 37.935+74.52 = 112.455 units^2 as our final answer

<u>Problem 4 (Bottom right):</u>

This irregular shape is an ellipse, but a circle is missing from its center. Thus, we must find the area of the circle and ellipse and then subtract the circle's area from the ellipse's area. For the area of the ellipse, a=(15.5/2)=7.75, and b=(7/2)=3.5, making its area A = π(7.75)(3.5) = 27.125π = 85.216 units^2. The area of a circle is A=πr² where "r" is the radius. The radius would be 7/2=3.5, making the circle's area A = π(3.5²) = 12.25π = 38.485 units^2. This means that the shaded area is 85.216-38.435 = 46.781 units^2  

6 0
3 years ago
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