I think the answer is <span>AM radio </span><span>waves. Im not sure but if its right can you mark my brainliest?
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Answer:
if the resistor is fitted in series with the bulb , then the current flowing will be 0.15 A.....
if the resistor if fitted in parallel with the bulb ,
the current flowing will be 0.6 A
Explanation:
total potential difference = 1.5V
when resistors in series ,
total equivalent resistance is = 5 + 5 = 10 ohm
so current = 1.5 ÷ 10 = 0.15
when resistors in parallel ,
total equivalent resistance is = (5 × 5)÷(5 + 5) =2.5 ohm
so current = 1.5÷2.5 = 0.6 A
Answer:
x = 41.28 m
Explanation:
This is a projectile launching exercise, let's find the time it takes to get to the base of the cliff.
Let's start by using trigonometry to find the initial velocity
cos 25 = v₀ₓ / v₀
sin 25 = Iv_{oy} / v₀
v₀ₓ = v₀ cos 25
v_{oy} = v₀ sin 25
v₀ₓ = 22 cos 25 = 19.94 m / s
v_{oy} = 22 sin 25 = 0.0192 m / s
let's use movement on the vertical axis
y = y₀ + v_{oy} t - ½ g t²
when reaching the base of the cliff y = 0 and the initial height is y₀ = 21 m
0 = 21 + 0.0192 t - ½ 9.81 t²
4.905 t² - 0.0192 t - 21 = 0
t² - 0.003914 t - 4.2813 =0
we solve the quadratic equation
t = 
t = 
t₁ = 2.07 s
t₂ = -2.067 s
since time must be a positive scalar quantity, the correct result is
t = 2.07 s
now we can look up the distance traveled
x = v₀ₓ t
x = 19.94 2.07
x = 41.28 m
Answer:
Such limitations are given below.
Explanation:
- Each pn junction provides limited measurements of maximum forwarding current, highest possible inversion voltage as well as the maximum output level.
- If controlled within certain adsorption conditions, the pn junction could very well offer satisfying performance.
- In connector operation, the maximum inversion voltage seems to be of significant importance.
