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anastassius [24]
3 years ago
7

Hi, I need your help with this Physics exercise, I hope you can help me A pulse moving to the right along the x axis is represen

ted by the function of wave: y (x, t) = 2 / (x-3t) ^ 2 + 1 Where x and are measured in centimeters and t in seconds. a) Find the velocity, pulse amplitude, and expressions for the wave function at t = 0s, t = 1.0s and t = 2.0 seconds. b) What would happen if the wave function were: y (x, t) = 2 / (x + 3t) ^ 2 + 1 How would this change the situation?
Physics
1 answer:
igomit [66]3 years ago
3 0

Answer:

Velocity = 0.309 m/s

Along negative x axis

Explanation:

A pulse moving to the right along the x axis is represented by the wave function

y(x,t) = 2/ (x - 3t)² + 1

At t =0

y(x,0) = 2/ ((x - 3(0))² + 1)

        =2 / (x² + 1)

At t = 1

y(x,t) = 2/ ((x - 3(1))² + 1)

= 2 /(( x - 3)² + 1)

At t = 2

y(x,t) = 2/ ((x - 3(2))² + 1)

= 2 /(( x - 6)² + 1)

For the pulse with expression y(x,t) = 4.5e^{-(8.73x + 2.70t)}²

The Velocity is

V = 2.7 / 8.73

= 0.309 m/s

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y_{o} = y-v_{o,y}\cdot t -\frac{1}{2}\cdot g\cdot t^{2}

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