Question

The graph of which inequality has open circles on -16 and 4 with a line segment between them?

Answer 1

Answer: Choice A.  $|x+6| < 10$

Explanation:

The rule is that stuff of the form $|x| < k$ becomes $-k < x < k$ where k is some positive number.

So we'll have these steps

$|x+6| < 10\\\\-10 < x+6 < 10\\\\-10-6 < x+6-6 < 10-6\\\\-16 < x < 4$

In the third step, I subtracted 6 from all sides to isolate x.

The last step indicates we'll have open holes at -16 and 4, with shading in between. It visually tells the reader "x can be anything between -16 and 4, but can't be equal to either endpoint".