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Tanzania [10]
3 years ago
11

Please help if you do I will give you 50 points and brainliest. I'll give you 50 points by posting another question just to make

it clear.

Physics
1 answer:
Zolol [24]3 years ago
6 0

Answer:

Name and Title: Lyric Howe, Mrs. Stefani, 9/20/17, Thermal Energy and Chemical Change Engineering Lab

Define the Problem:To understand thermal energy and chemical changes better by building my own train.

Criteria and Limitations—In this section, please list at least three criteria that must be met by your train design. Also include any limitations that could prevent it from getting its cargo to the station.

Criteria Limitations One steam engine  Two separate hills  One cargo box Missing tracks  Stack items across or atop each other Weight

Design Ideas—Pros and Cons:In this section, describe three design ideas you have for your train. List at least one pro (a positive) and one con (a negative) for each design option

Description of Train Design One Wheels first with two springs underneath each wheel, the panda cargo in the middle with the steam engine in the front, and two sets of helium balloons.

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A student is bouncing on a trampoline. at her highest point, her feet are 65 cm above the trampoline. when she lands, the trampo
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<span>she is in contact with the trampoline for less than one second.</span>
3 0
3 years ago
Three +3.0-μC point charges are at the three corners of a square of side 0.50 m. The last corner is occupied by a −3.0-μC charge
Naddik [55]

Answer:

4.30 x 10⁵ N/C

Explanation:

Two positive +3.0-μC point charges at opposite corners of the square creates equal and opposite electric field at the center. hence the electric field by these two positive charges at opposite corners becomes zero.

a = length of the square of side = 0.50 m

r = distance of the center from each corner = \frac{a}{sqrt(2)} = \frac{0.50}{sqrt(2)} = 0.354 m

Magnitude of net electric field at the center is given as

E = \frac{2kq}{r^{2}} \\E = \frac{2(8.99\times10^{9})(3\times10^{-6})}{(0.354)^{2}} \\E = 4.30\times10^{5} NC^{-1}

6 0
3 years ago
POINTS + BRAINLIEST TO CORRECT ANSWER
Tpy6a [65]

Answer:kahhot.it

Explanation:hghh

3 0
4 years ago
Склянка с воздухом закрыта «пробкой» из мыльной пены.
alexira [117]
Склянка с воздухом закрыта «пробкой» из мыльной пены.
Определи, что произойдёт, если склянку частично погрузить в ёмкость с горячей водой?

Выбери правильный вариант ответа.
Мыльная пена будет перемещаться внутрь склянки.
Мыльная пена будет подниматься наружу.

Что произойдёт с давлением воздуха внутри склянки?
Выбери правильный вариант ответа.
Давление не изменится.

и дальнейшее объяснение произошедшего

Может показаться, что воздух в вашей бутылке - просто пустое пространство, но на самом деле это смесь газов. Сила, с которой отдельные молекулы отскакивают от внутренней и внешней стороны бутылки, называется давлением.
5 0
3 years ago
point) A circular swimming pool has a diameter of 12 m. The circular side of the pool is 3 m high, and the depth of the water is
Sergio [31]

Answer:

(a) 86.65 J

(b) 149.65 J

Solution:

As per the question:

Diameter of the pool, d = 12 m

⇒ Radius of the pool, r = 6 m

Height of the pool, H = 3 m

Depth of the pool, D = 2.5 m

Density of water, \rho_{w} = 1000\ kg//m^{3}

Acceleration due to gravity, g = 9.8\ m/s^{2}

Now,

(a) Work done in pumping all the water:

Average height of the pool, h = \frac{H + D}{2}

h = \frac{3 + 2.5}{2} = 2.75\ m

Volume of water in the pool, V = \pi r^{2}h = \pi \times 6^{2}\times 2.75 = 311.02\ m^{3}

Mass of water, m_{w} = \frac{\rho_{w}}{V}

m_{w} = \frac{1000}{311.02} = 3.215\ kg

Work done is given by the potential energy of the water as:

W = m_{w}gh = 3.215\times 9.8\times 2.75 = 86.65\ J

(b) Work done to pump all the water through an outlet of 2 m:

Now,

Height, h = 2.75 + 2 = 4.75

Work done,W = m_{w}gh = 3.215\times 9.8\times 4.75 = 149.65\ J

7 0
3 years ago
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