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antoniya [11.8K]
3 years ago
11

A 66.0-kg boy and his 45.0-kg sister, both wearing roller blades, face each other at rest. The girl pushes the boy hard, sending

him backward with a velocity 2.80 m/s toward the west. Ignore friction. (a) Describe the subsequent motion of the girl.
Physics
1 answer:
lesya [120]3 years ago
6 0

Answer:

the girl moves towards right with a velocity of 4.1m/s

Explanation:

Since the system is isolated the momentum of the system is conserved

Initial momentum = Final Momentum

Since initially the system is at rest thus \overrightarrow{p_{i}}=0

Now the final momentum of boy = m_{boy}×velocity

\overrightarrow{p_{boy}}=66.0\times -2.80m/s\\\\\overrightarrow{p_{boy}}=-184.8kgm/s

Now for girl let the velocity = u hence her moumentum is 45\times u

Thus equating final momentum to zero we have

-184.8kgm/s+45\times u = 0

u=\frac{184.8}{45}m/s

hence u=4.1m/s

Thus the girl moves towards right with a velocity of 4.1m/s

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