Sqrt(486) - sqrt(24) + sqrt(6)
find the factors of 486 that we can remove from under the square root sign
2 * 243
2 * 3 * 81
2 * 3 * 9 * 9 (we have 2 nines, we can move a 9 outside the sqrt sign)
sqrt(486) = 9 sqrt(6)
Repeating for sqrt(24)
2 * 12
2 * 2 * 6
2 * 2 * 2 * 3 (we can move a 2 outside the sqrt
sqrt(24) = 2 sqrt(6)
Finally, add all 3 terms together
9 sqrt(6) - 2 sqrt(6) + sqrt(6)
8 sqrt(6)
8 times square root of 6 is the final answer
Answer:
if 
and 
.
Step-by-step explanation:
We are given and .
We are asked to find 
.
means 
You only have one pair of like terms, that is the constants.
Answer:
Sheila have 6 bills
Step-by-step explanation:
Suppose Sheila has x '20' dollar bills, so the total cost of her bill = $20x
Suppose Tamsin has y '10' dollar bills, so the total cost of her bill = $10y
<h3>Equation 1</h3>
<em>Sheila has a total of $50 more than Tamsin</em>
<h2><em>10y + 50 = 20x</em></h2><h2 /><h3>
Equation 2</h3>
<em>Tamsin has 1 more bill than Sheila.</em>
<h2>y = x + 1 </h2><h2 />
<em>Now solve them by putting value of x in equation </em>
10( x + 1 ) + 50 = 20x
10x + 10 + 50 = 20x
60 = 20x - 10x
10x = 60
x = 60/10
x = 6
and
y = 7
<em> </em>
